Line Chart - 8
Practice and master this topic with our carefully crafted questions.
Two different finance companies declare fixed annual rate of interest on the amounts invested with them by investors. The rate of interest offered by these companies may differ from year to year depending on the variation in the economy of the country and the banks rate of interest. The annual rate of interest offered by the two Companies P and Q over the years are shown by the line graph provided below.
Annual Rate of Interest Offered by Two Finance Companies Over the Years.

Difference = ₹ [(10% of 4.75) - (8% of 4.75)] lakhs
= ₹ (2% of 4.75) lakhs
= ₹ 0.095 lakhs
= ₹ 9500.
Amount received from Company P after one year (i.e., in 199) on investing ₹ 12 lakhs in it
= ₹ [12 + (8% of 12)] lakhs
= ₹ 12.96 lakhs.
Amount received from Company P after one year on investing ₹ 12.96 lakhs in the year 1999
= ₹ [12.96 + (10% of 12.96)] lakhs
= ₹ 14.256.
Appreciation received on investment during the period of two years
= ₹ (14.256 - 12) lakhs
= ₹ 2.256 lakhs
= ₹ 2,25,600.
Amount received from Company Q after one year on investment of ₹ 5 lakhs in the year 1996
= ₹ [5 + (6.5% of 5)] lakhs
=₹ 5.325 lakhs.
Amount received from Company P after one year on investment of ₹ 5.325 lakhs in the year 1997
= ₹ [5.325 + (9% of 5.325)] lakhs
= ₹ 5.80425 lakhs
= ₹ 5,80,425.
Let the amounts invested in 2002 in Companies P and Q be ₹ 8x and ₹ 9x respectively.
| Then, interest received after one year from Company P | = ₹ (6% of 8x) | ||||
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| and interest received after one year from Company Q | = ₹(4% of 9x) | ||||
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Required ratio = |
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= | 4 | . | |||||
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3 |
Let ₹ x lakhs be invested in Company P in 2000, the amount invested in Company Q in 2000 = ₹ (30 - x) lakhs.
Total interest received from the two Companies after 1 year
= ₹ [(7.5% of x) + {9% of (30 - x)}] lakhs
| = ₹ | ![]() |
2.7 - | ![]() |
1.5x | ![]() |
![]() |
lakhs. |
| 100 |
|
![]() |
2.7 - | ![]() |
1.5x | ![]() |
![]() |
= 2.43 x = 18. |
| 100 |
Required ratio =


![]](/assets/images/data-interpretation/common/15-sym-cbracket-h1.gif)
x = 18.