Quantitative Aptitude

General Questions 3

Quantitative Aptitude Exercise Mode

General Questions 3

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Question 11
In a town 25% families own a phone and 15% own a car, 65% families own neither a phone nor a car. 2000 families own both a phone and a car. Consider the following statement in this regard.

(i) 10% families own both a car and a phone.

(ii) 35% families own either a car or a phone.

(iii) 40000 families live in the town.

Which of the above statement are correct?

A
I and II
B
I and III
C
II and III
D
I, II and III
Correct Answer: Option C

Suppose N% families own both a car and a phone,

Then,

percentage of the families owing only a phone = 25 - N

Percentage of the families owing only a car = 15 - N

 (25 - N) +(15 - N) + N + 65 = 100

 N = 5

Percentage of families who have either a car or a phone = (25 - 5) + (15 - 5) + 5 = 35

So, Statement ll is correct.


 Now, suppose the total number of families in the town be A.

(5 x A)/100 = 2000   A = 40000

So, Statement lll is also correct.

Question 12
The price of rice is reduced by 5%. How many kilograms of rice can now be bought for the money, which was sufficient to buy 50 kg of rice earlier?

A
52.63 kg
B
50.40 kg
C
42.30 kg
D
60.50 kg
Correct Answer: Option A

Let original price be ₹ 100 per kg.

Money required to buy 50 kg of rice = ₹ (100 x 50) = ₹ 5000

New price = (100 - 5) = ₹ 95 per kg

 Quantity of rice bought = (5000/95) kg = 52.63 kg

Question 13
In a class -X of 30 students, 24 passed in first class; in another class -Y of 35 students, 28 passed in first class. In which class was the percentage of students first class more?

A
Class X has more percentage of students getting first class
B
Class Y has more percentage of students getting first class
C
Both classes have equal percentage of students getting first class
D
None of the above
Correct Answer: Option C

For class X, let the students passed in first class = a%

Then, by condition given in question

a% of 30 = 24

 (a x 30) /100 = 24

 a = 80%


Now, for class Y let the student passed in first class = b%

Then, according to the question,

b% of 35 = 28

 (b x 35)/100 = 28

b = (28 x 100)/35 = 80%

Hence, both classes have equal percentage of student getting first class.

Question 14
In an examination, 49% students failed in English, 36% students failed in Hindi, While 15% failed in both. If total number of passed students in 450, then how many students did appear in the examination?

A
1800
B
2000
C
1100
D
1500
E
None of the above
Correct Answer: Option D

According to the formula .

Percentage of students passed in both the subjects

= [100 - (x + y - z)]%

= [100 - (49 + 36 - 15)]% = 30%


Let total number of students = N

According to the question,

 (N x 30)/100 = 450

 N = (450/30) x 100 = 1500

 Total number of students = 1500

Question 15
A student was asked to measure the length and breadth of a rectangle. By mistake, he measured the length 20% less and the breath 10% more. If it’s original area is 200 sq cm, then find the area after this measurement?

A
176 sq cm
B
206 sq cm
C
226 sq cm
D
316 sq cm
Correct Answer: Option A

Net effect on area = -20 + 10 + [(-20 )(10)/100] %

= (-10 - 2) % = -12%

Now, after this mistake new area = (100 - 12)% of 200

= (88/100) x 200

= 176 sq cm

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