General Questions 3
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In 1998
Let number of students in x = 3k
Number of students in y = 5k and
Number of students in z = 6k
Next year,
Number of students in x = 3k + 20% of 3k = 18k/5 ------- (i)
Number of students in y = 5k + 10% of 5k = 11k/2 ------- (ii)
Number of students in z = 6k + 20% of 6k = 36k/5 -------- (iii)
According to the question, (i) & (iii)
(18k/5) / (36k/5) = 1/2
Thus, Data is insufficient.
Total number of students = 480
percentage of total students passed = 75% of total student
= (75 x 480)/100 = 360 students
Now, using the condition from the question.
Let the number of boys be N
Then, 70% of N + 85% of (480 - N) = 360
⇒ [(70 x N)/100] + [85 x (480 - N)]/100 = 360
⇒ 70N - 85N + 40800 = 36000
⇒ 40800 - 36000 = 85N - 70N
⇒ 4800 = 15N
⇒ N = 4800/15 = 320
∴ There are 320 boys who appeared for the examination.
Let number of boys be 300.
Number of girls = 200
Boys holding scholarship = (20/100) x 300 = 60
Girls holding scholarship = (25/100) x 200 = 50
Total student holding scholarship = 60 + 50 = 110
∴ Percentage of students not holding scholarship = [(500 -110) / 500] x 100%
⇒ (390/500) x 100 %
⇒ 78%
Let price of ghee before increment = ₹N
Consumption = 10 kg
Then, expenditure on ghee = ₹10N
After increment,
Expenditure on ghee = 110% of 10N = 11N
Price of ghee = 132% of N = (N x 132)/100 = 33N/25 per kg
∴ Now consumption = (11N x 25) / 33N kg
= 8(1/3)
Let the number of boys = x
Then, x + 7x/10 = 85
x = 50
No. of girls = 85 - 50 = 35
(i) Number of boys playing only badminton = 50% of boys
= 50/100 x 50 = 25
(ii) Number of children playing only table tennis
= 40% of total no. of children
= 40/100 x 85 = 34
(iii) Total no. of children playing both badminton and table tennis = 12
Hence, number of girls playing only badminton = 85 - (25 + 34 + 12)
= 85 - 71 = 14.
Let total number of employee be 100.
∴ Number of men = 60% of 100 = 60
and number of women = 40% of 100 = 40
Number of Men drawing more than ₹50000 = 40% of 60 = 24 Men
Since, number of total employees drawing more than ₹ 50000 = 36% of 100 = 36
∴ Number of women who more than ₹ 50000 = 36 - 24 = 12
∴ Number of women who draw less than ₹ 50000 = 40 - 12 = 28
Percentage of Women who draw less then ₹ 50000 per year = (28 x 100)/40 = 70%
Let a student was awarded in exam = N marks
According to the question,
After re-evaluation his score
N - N x (40/100) = 96
N - 2N/5 = 96
5N - 2N/5 = 96
3N/5 = 96
N = (5 x 96)/3 = 5 x 32
N = 160
So, a student was awarded by 160 marks in examination
Reduced marks after re-evaluation = 160 - 96 = 64
Gold in 50g of alloy = (80 x 50)/100 = 40 g
Let W gram gold must be added.
Now, according to the question,
(40 + W) / (50 + W) = 90/100
100( 40 + W) = 90 (50 + W)
10(40 + W) = 9 (50 + W)
400 + 10W = 450 + 9W
W = 450 - 400
W = 50g
Thus, 50 g of gold must be added to make it 90%
Let us assume that Arun uses N units of petrol everyday. so the amount of of petrol in the tank when it is full will be 10N. If he starts using 25% more petrol everyday. then the units of petrol he now use everyday will be
N(1 + 25/100) = 1.25N
So, the number of days his petrol will now last will be equal to (amount of petrol in tank) / (number of units used everyday)
= (10N) / (1.25N) = 10 / 1.25
= 8 days
Number of sweets received by every students
= 15% of 40 = (40 x 15)/100 = 6
Number of sweets received by 40 students = 40 x 6 = 240
Number of sweets received by each teacher = 20% of 40 = (40 x 20)/100 = 8
Number of sweets received by 5 teachers = 8 x 5 = 40
Total number of sweets = 240 + 40 = 280