Data Interpretation
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Pie Chart 2
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Study the following graph and the table and answer the questions given below.
Data of different states regarding population of states in the year 1998

Total population of the given States = 3276000.
| States | Sex and Literacy wise Population Ratio | |||
| Sex | Literacy | |||
| M | F | Literate | Illiterate | |
| A.P | 5 | 3 | 2 | 7 |
| M.P | 3 | 1 | 1 | 4 |
| Delhi | 2 | 3 | 2 | 1 |
| Goa | 3 | 5 | 3 | 2 |
| Bihar | 3 | 4 | 4 | 1 |
| U.P. | 3 | 2 | 7 | 2 |
| T.N. | 3 | 4 | 9 | 4 |
Question 1
What was the total number of illiterate people in A.P. and M.P. in 1998 ?
Correct Answer: Option D
| No. of illiterate people in A.P. |
| = | ![]() | 7 | of (25% of 3276000) | ![]() | = 637000. |
| 9 |
| No. of illiterate people in M.P. |
| = | ![]() | 4 | of (20% of 3276000) | ![]() | = 524160. |
| 5 |
Total number = (637000 + 524160) = 1161160.
Question 2
What was the number of males in U.P. in the year 1998 ?
Correct Answer: Option B
Number of males in U.P.
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Question 3
What will be the percentage of total number of males in U.P. , M.P. and Goa together to the total population of all the given states ?
Correct Answer: Option C
Number of males in U.P
Total numbers of males in these three states
| = | ![]() | 3 | of (15% of N) | ![]() | = | 3 | x | 15 | = 9 x | N | . |
| 5 | 5 | 100 | 100 |
where N = 3276000.
Number of males in M.P| = | ![]() | 3 | of (20% of N) | ![]() | = | 3 | x | 20 | x N = 15 x | N | . |
| 4 | 4 | 100 | 100 |
Number of males in Goa
| = | ![]() | 3 | of (12% of N) | ![]() | = | 3 | x | 12 | x N = 4.5 x | N | . |
| 8 | 8 | 100 | 100 |
28.5 x N/100![]() Required Percentage
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Question 4
What is the ratio of the number of females in T.N. to the number of female in Delhi ?
Correct Answer: Option D
| Required ratio |
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Question 5
If in the year 1998, there was an increase of 10% in the population of U.P. and 12% in the population of M.P. compared to the previous year, then what was the ratio of populations of U.P. and M.P. in 1997 ?
Correct Answer: Option A
Let x be the population of U.P. in 1997. Then,
| Population of U.P. in 1998 = 110% of x = | 110 | x x. |
| 100 |
Also, let y be the population of M.P. in 1997. Then,
| Population of M.P. in 1998 = 112% of y = | 112 | x y. |
| 100 |
| Ratio of populations of U.P. and M.P. in 1998 |
| = |
| = | 110x | . | |||||
| 112y |
| From the pie-chart, this ratio is | 15 | . |
| 20 |
![]() | 110x | = | 15 | | x | = | 15 | x | 112 | = | 42 | . |
| 112y | 20 | y | 20 | 110 | 55 |
Thus, ratio of populations of U.P. and M.P. in 1997
= x : y = 42 : 55.

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28.5 x N/100

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