Arithmetic Reasoning - Base Level
Practice and master this topic with our carefully crafted questions.
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.
Then, 2x + 3y = 77 ...(i) and
3x + 2y = 73 ...(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.
Since each pole at the corner of the plot is common to its two sides.
Therefore total number of poles needed = 27 × 4 - 4 = 104.
Originally, let number of women = x. Then number of men = 2x.
So, in city Y, we have (2x - 10) = (x + 5 ) or x = 15.
Total number of passengers in the beginning = ( x + 2x) = 3x = 45.
Total number of routes from Bristol to Carlisle = ( 4 × 3 × 2) = 24.
Let the number be x.
Then x + 13x = 112 ‹=›14x = 112 ‹=› x = 8.
Let number of girls = x and number of boys = 3x.
Then, 3x + x = 4x = total number of students.
Thus, to find exact value of x,
The total number of students must be divisible by 4.
L.C.M. of 6,5,7,10 and 12 is 420.
So, the bells will toll together after every 420 seconds. i.e. 7 minutes.
Now 7 × 8 = 56 and 7 × 9 = 63.
Thus, in 1 hour( or 60 minutes), the bells will toll together 8 times, excluding the one at the start.
Let R, G and B represent the number of balls in red, green and blue boxes respectively.
Then,
R + G + B = 108 ...(i),
G + R = 2B ...(ii)
B = 2R ...(iii)
From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.
Putting G = 3R and B = 2R in (i), we get:
R + 3R + 2R = 108 => 6R = 108 => R = 18.
Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.
The seven pieces consist of 6 smaller equal pieces and one calf cake piece.
Weight of each small piece = 20 g.
So, total weight of the cake = [2 × (20 × 6)]g = 240g.
Let son’s age be x years.
Then father’s age = (3x) years.
Five years ago, father’s age = (3x - 5) years and
Son’s age = (x - 5) years.
So 3x - 5 = 4 (x - 5)‹=›3x - 5 = 4x - 20 ‹=› x = 5.