General Questions
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Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y.
| Then, 4x + 6y = | 1 | and 3x + 7y = | 1 | . |
| 8 | 10 |
Solving the two equations, we get:
| x = | 11 | , y = | 1 |
| 400 | 400 |
1 woman's 1 day's work = |
1 | . |
| 400 |
10 women's 1 day's work = |
![]() |
1 | x 10 | ![]() |
= | 1 | . |
| 400 | 40 |
Hence, 10 women will complete the work in 40 days.
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x x = |
![]() |
4 x 20 | ![]() |
| 5 |
x = 16 days.
Ratio of times taken by A and B = 100 : 130 = 10 : 13.
Suppose B takes x days to do the work.
Then, 10 : 13 :: 23 : x
x = |
![]() |
23 x 13 | ![]() |
x = |
299 | . |
| 10 | 10 |
| A's 1 day's work = | 1 | ; |
| 23 |
| B's 1 day's work = | 10 | . |
| 299 |
(A + B)'s 1 day's work
| = | ![]() |
1 | + | 10 | ![]() |
= | 23 | = | 1 | . |
| 23 | 299 | 299 | 13 |
Therefore, A and B together can complete the work in 13 days.
Formula: If A can do a piece of work in n days,
| then A's 1 day's work = | 1 | . |
| n |
| (A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 7 | . |
| 24 | 6 | 12 | 24 |
| Formula: If A's 1 day's work = | 1 | , | |
| n |
then A can finish the work in n days.
So, all the three together will complete the job in:
![]() |
24 | days |
= | 3 | 3 | days. | |
| 7 | 7 |
| Work done by X in 4 days = | ![]() |
1 | x 4 | ![]() |
= | 1 | . |
| 20 | 5 |
| Remaining work = | ![]() |
1 - | 1 | ![]() |
= | 4 | . |
| 5 | 5 |
| (X + Y)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 8 | = | 2 | . |
| 20 | 12 | 60 | 15 |
| Now, | 2 | work is done by X and Y in 1 day. |
| 15 |
| So, | 4 | work will be done by X and Y in | ![]() |
15 | x | 4 | ![]() |
|
| 5 | 2 | 5 |
= 6 days.
Hence, total time taken = (6 + 4) days = 10 days.
Number of pages typed by Ravi in 1 hour
| = | 32 | = | 16 | . |
| 6 | 3 |
Number of pages typed by Kumar in 1 hour
| = | 40 | = 8. |
| 5 |
Number of pages typed by both in 1 hour
| = | ![]() |
16 | + 8 | ![]() |
= | 40 | . |
| 3 | 3 |
Time taken by both to type 110 pages
| = | ![]() |
110 x | 3 | ![]() |
hours |
| 40 |
| = 8 | 1 | hours (or) 8 hours 15 minutes. |
| 4 |
Ratio of rates of working of A and B = 2 : 1.
So, ratio of times taken = 1 : 2.
| B's 1 day's work = | 1 | . |
| 12 |
A's 1 day's work = |
1 | ; (2 times of B's work) |
| 6 |
| (A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 3 | = | 1 | . |
| 6 | 12 | 12 | 4 |
So, A and B together can finish the work in 4 days.
Suppose A, B and C take :
| x, | x | and | x | days respectively to finish the work. |
| 2 | 3 |
| Then, | ![]() |
1 | + | 2 | + | 3 | ![]() |
= | 1 |
| x | x | x | 2 |
|
6 | = | 1 |
| x | 2 |
x = 12.
So, B takes (12/2) = 6 days to finish the work.
(20 x 16) women can complete the work in 1 day.
1 woman's 1 day's work = |
1 | . |
| 320 |
(16 x 15) men can complete the work in 1 day.
1 man's 1 day's work = |
1 |
| 240 |
| So, required ratio |
|
||||||
|
|||||||
| = 4 : 3 (cross multiplied) |
| (A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
| 15 | 10 | 6 |
| Work done by A and B in 2 days = | ![]() |
1 | x 2 | ![]() |
= | 1 | . |
| 6 | 3 |
| Remaining work = | ![]() |
1 - | 1 | ![]() |
= | 2 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 15 |
|
2 | work will be done by a in | ![]() |
15 x | 2 | ![]() |
|
| 3 | 3 |
= 10 days.
Hence, the total time taken = (10 + 2) = 12 days.

