General Questions
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A's 1 days work=1/10 and B 's 1 days work = 1/15.
∴ (A + B)'s 1 day's work = 1/10 + 1/15 = 1/6.
So, both together will finish the work in 6 days.
| C's 1 day's work = | 1 | - | ![]() |
1 | + | 1 | ![]() |
= | 1 | - | 7 | = | 1 | . |
| 3 | 6 | 8 | 3 | 24 | 24 |
A's wages : B's wages : C's wages
| = | 1 | : | 1 | : | 1 | = 4 : 3 : 1. |
| 6 | 8 | 24 |
C's share (for 3 days)
= ₹ |
![]() |
3 x | 1 | x 3200 | ![]() |
= ₹ 400. |
| 24 |
| A's 2 day's work = | ![]() |
1 | x 2 | ![]() |
= | 1 | . |
| 20 | 10 |
(A + B + C)'s 1 day's work
| = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
| A's 1 day's work = | 1 | ; |
| 15 |
| B's 1 day's work = | 1 | ; |
| 20 |
| (A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 7 | . |
| 15 | 20 | 60 |
| (A + B)'s 4 day's work = | ![]() |
7 | x 4 | ![]() |
= | 7 | . |
| 60 | 15 |
| Therefore, Remaining work = | ![]() |
1 - | 7 | ![]() |
= | 8 | . |
| 15 | 15 |
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes
![]() |
3 | x 60 | ![]() |
= 90 days. | |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
A and B together can do the work in
| 45 | = 22 | 1 | days. | |
| 2 | 2 |
| (A + B + C)'s 1 day's work = | 1 | , |
| 4 |
| A's 1 day's work = | 1 | , |
| 16 |
| B's 1 day's work = | 1 | . |
| 12 |
C's 1 day's work
| = | 1 | - | ![]() |
1 | + | 1 | ![]() |
= | ![]() |
1 | - | 7 | ![]() |
= | 5 | . |
| 4 | 16 | 12 | 4 | 48 | 48 |
| So, C alone can do the work in | 48 | = 9 | 3 | days. |
| 5 | 5 |
(A + B)'s 1 day's work = (1/30 + 1/40) = 7/120
∴ Time taken by both to finish the work = 120/7days = 171/7 days
B's 9 day's work = 9 x (1/12) = 3/4
Remaining work = (1 - 3/4) = 1/4
∴ 1/4 work is done by A in = 20 x (1/4) = 5 days.
of a work in 5 days and B can do
of the work in 10 days. In how many days both A and B together can do the work ?∵ 1/3 of work is done by A in 5 days.
∴ Whole work will be done by A in 15 days.
∵ 2/3 of work is done by B in 10 days.
Whole work will be done by B in 10 x (5/2) i.e., 25days
∴ (A + B)'s 1 day's work = (1/15 + 1/25) = 8/75
So, both together can finish it in 75/8 days, i.e., 93/8 days.
(A + B)'s 1 day's work = 1/18
(B + C)'s 1 day's work = 1/24
(A + C)'s 1 day's work = 1/36
Adding 2 (A + B + C)'s 1 day's work = (1/18 + 1/24 + 1/36) = 1/8
∴ (A + B + C)'s day's work = 1/16
Hence, all working together can finish it in 16 days.

