Quantitative Aptitude

General Questions

Quantitative Aptitude Exercise Mode

General Questions

Practice and master this topic with our carefully crafted questions.

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QUEST ? !
Question 11
Rohan and Sunil separately can complete a work in 8 hours and 4 hours respectively. How much time will they take when working together ?

A
22/3 hours
B
11/3 hours
C
3 hours
D
2 hours
Correct Answer: Option A

Required time taken to complete the work by both together = x y / x + y

(Here x = 8 and y = 4)

∴ Required time = (8 x 4)/(8 + 4) = 32/12 = 22/3 hours

Question 12
A is twice as good a workman as B and together they finish a piece of work in 14 days. In how many days can a alone finish the work?

A
18
B
20
C
21
D
24
Correct Answer: Option C

One day's work of A and B = 1/x + 1/2x = 1/14

∴ x = 21

Since A is twice efficient as B so A will take half of the day taken by B.

Question 13
X can do a work in 16 days. In how many days will the work be completed by Y, if the efficiency of Y is 60% more than that of X ?

A
10 days
B
12 days
C
25 days
D
30 days
Correct Answer: Option A

Ratio of time taken by X

and Y = 160 : 100 = 16 : 1

Suppose Y takes y days to the work.

Then, 1.6 : 1 = 16 : y

∴ y = (16 x 1)/1.6 = 10 days

Question 14
A alone can do a certain job in 15 days, while B alone can do it in 10 days. A started the work and was joined by B after 5 days. The work lasted for how many days ?

A
4
B
8
C
5
D
9
Correct Answer: Option D

A's 5 days' work = (1/15) x 5 = 1/3

Remaining work = 1 - (1/3) = 2/3

∴ (A + B)'s 1 day's work = (1/15) + (1/10)

= 5/30

= 1/6

∴ 2/3 work will be finished by (A + B) in (2/3) x 6 days or in 4 days .

∴ Total time taken = (5 + 4) days = 9 days

Question 15
A does 20 % less work then B. If A can complete a piece of work in 7h, then B can do it in:

A
4 h
B
6 h
C
8 h
D
10 h
Correct Answer: Option B

Let time taken by B = N

Efficiency ∝ 1/Time taken

So, if B is 100% efficient, then A is 80% efficient.

So, 80/100 = N /(15/2)

∴ N = 6 h

Question 16
X can completed a job in 12 days. If X and Y work together, they can complete the job in 6 days, Y alone can complete the job in:

A
10 days
B
12 days
C
15 days
D
18 days
Correct Answer: Option C

X's 1 day's work = 1/12

(X + Y)' s 1 day's work = 3/20

∴ Y's 1 day's work = (3/20) - (1/12) = 4/60 = 1/15

∴ Number of day's taken by Y to complete the work = 15 days

Question 17
3 men can do a piece of work in 6 days. 5 women can do the same work in 18 days. If 4 men and 10 women work together, then how long will it take to finish the work ?

A
3 days
B
5 days
C
2 days
D
4 days
E
None of the above
Correct Answer: Option A

(3 x 6) men = (5 x 18) women

18 men = 90 women

∴ 1 man = 5 women

∴ 4 men + 10 women

= 4 x 5 + 10 = 30 women

Given, M1 = 5, M2 = 20, D1 = 18 ,

W1 = W2 = 1 and D2 = ?

According to the formula, M1D1W2 = M2D2W1

⇒ 5 x 18 x 1 = 30 x D2 x 1

∴ D2 = 5 x 18/30 = 3 days

Question 18
P can do piece of work in 12 days, while Q alone can finish it in 8 days. With the help of R, they can finish the work in 4 days. How long will R take to finish the work alone ?

A
25 days
B
34 days
C
14 days
D
24 days
E
None of the above
Correct Answer: Option D

P's 1 day's work = 1/12

Q's 1 day's work = 1/8

(P + Q)'s 1 day's work = (1/12) + (1/8)

= (2 + 3)/24

= 5/24


(P + Q + R)'s 1 day's work = 1/4

∴ R's 1 day's work = (1/4) - (5/24) = (6 - 5)/24 = 1/24

∴ R will finish the work alone in 24 days.

∴ Required time = 24 days

Question 19
3 men can do a piece of work in 18 days. 6 children can also do that work in 18 days. 4 men and 4 children together will finish the work in how many days ?

A
10
B
6
C
12
D
19
E
None of the above
Correct Answer: Option D

3 men = 6 children

⇒ 1 man = 2 children

∴ 4 men + 4 children = 4 men + (4/2) men = 6 men

Given, M1 = 3, M2 = 6, D1 = 18, W1 = W2 = 1 and D2= ?


According to the formula,

M1D1W2 = M2D2W1

⇒ 3 x 18 x 1 = 6 x D2 x 1

∴ D2 = 3 x 18/6 = 9 days

Question 20
10 men can make a wall in 8 days. How many men required to complete the same work in half days ?

A
80
B
100
C
120
D
160
Correct Answer: Option D

Given M1 = 10

D1 = 8, M2= ? and D2 = 1/2

From M1 D1 = M2 D2

⇒ 10 x 8 = M2 x 1/2

⇒ M2= 10 x 8 x 2

∴ M2 = 160