A can finish a job in 10 days and B in 15 days. How long will they take working together?
LCM method: job = 30 units
A = 3 units a day, B = 2 units a day
Together = 5 units a day
Days = 30 ÷ 5 = 6
Trap: averaging 10 and 15 gives 12.5.
Answer: 6 days
Time and Work · Exercise 1 of 5
40 time and work questions at competitive-exam level: combined rates, pairs of workers, efficiency comparisons, alternate days, leaving early, work and wages. Every solution uses the LCM (unit) method one step per line.
A can finish a job in 10 days and B in 15 days. How long will they take working together?
LCM method: job = 30 units
A = 3 units a day, B = 2 units a day
Together = 5 units a day
Days = 30 ÷ 5 = 6
Trap: averaging 10 and 15 gives 12.5.
Answer: 6 days
A can do a piece of work in 12 days and B in 24 days. In how many days can they finish it together?
Job = 24 units; A = 2, B = 1 a day
Together = 3 a day
Days = 24 ÷ 3 = 8
Answer: 8 days
A and B together finish a job in 12 days, and A alone in 20 days. How long will B alone take?
B's rate = 1/12 − 1/20 = (5 − 3)/60 = 1/30
B alone = 30 days
Trap: 20 − 12 = 8 subtracts days, not rates.
Answer: 30 days
A is twice as efficient as B, and together they finish a job in 18 days. How long would A alone take?
A = 2 units a day, B = 1 → together 3
Job = 3 × 18 = 54 units
A alone = 54 ÷ 2 = 27 days
Trap: 54 days is B alone.
Answer: 27 days
A can do one-fourth of a job in 5 days, and B can do one-third of it in 10 days. How long will they take together?
A alone = 20 days; B alone = 30 days
Job = 60 units; A = 3, B = 2 a day
Days = 60 ÷ 5 = 12
Answer: 12 days
A can finish a job in 15 days. He works for 5 days, and B finishes the rest in 12 days. How long would B alone take?
A did 5/15 = 1/3 → 2/3 left
B does 2/3 in 12 days
B alone = 12 × 3/2 = 18 days
Answer: 18 days
A, B and C can finish a job in 10, 12 and 15 days. How long will they take together?
Job = 60 units; rates 6, 5, 4 → 15 a day
Days = 60 ÷ 15 = 4
Answer: 4 days
A and B can finish a job in 10 days, B and C in 15 days, and C and A in 12 days. How long will all three take together?
Job = 60 units; A+B = 6, B+C = 4, C+A = 5 a day
Adding: 2(A + B + C) = 15 → A + B + C = 7.5
Days = 60 ÷ 7.5 = 8
Answer: 8 days
A and B can finish a job in 10 days, B and C in 15 days, and C and A in 12 days. How long will A alone take?
All three = 1/8 a day
A = 1/8 − (B + C) = 1/8 − 1/15 = 7/120
A alone = 120/7 = 17 1/7 days
Answer: 17 1/7 days
A is 25% more efficient than B. B alone can finish a job in 25 days. How long will A alone take?
Rates A : B = 5 : 4 → times A : B = 4 : 5
A = 25 × 4/5 = 20 days
Trap: 18.75 takes 25% off the time.
Answer: 20 days
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