Quantitative Aptitude

General Questions

Quantitative Aptitude Exercise Mode

General Questions

Practice and master this topic with our carefully crafted questions.

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Question 11
Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour ?

A
9
B
10
C
12
D
20
Correct Answer: Option B

Due to stoppages, it covers 9 km less.

∴ Time taken to cover 9 km = (9/54 x 60) min = 10 min.

Question 12
A train can travel 50% faster than a car . Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is :

A
100 kmph
B
110 kmph
C
120 kmph
D
130 kmph
Correct Answer: Option C

Let speed of the car be X kmph.

Then, speed of the train = (150 x X /100) = 3X/2 kmph.
=> 75/X - 75/1.5X = (125/10 x 60)

=> 75/X - 50/X = (5/24)

∴ X = (25 x 24 / 5) = 120 kmph.

Question 13
A man on tour travels first 160 km/hr at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is :

A
35.55 km/hr
B
36 km/hr
C
71.11 km/hr
D
71 km/hr
Correct Answer: Option C

Total time taken = (160/64 + 160/8) hrs = 9/2 hrs.

∴ Average speed = (320 x 2/9) km/hr = 71.11 km/hr.

Question 14
A boy rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. His average speed for the entire trip is approximately :

A
10.4 km/hr
B
10.8 km/hr
C
11 km/hr
D
12.2 km/hr
Correct Answer: Option B

Total distance travelled = (10 + 12) km/hr = 22 km/hr

Total time taken = (10/12 + 12/10) hrs = 61/30 hrs.

∴ Average speed = (22 x 30/61) km/hr = 10.8 km/hr

Question 15
A car travels the first one-third of a certain distance with a speed of 10 km/hr, the next one-third distance with a speed of 20 km/hr, and the last one-third distance with a speed of 60 km/hr. The average speed of the car for the whole journey is :

A
18 km / hr
B
24 km / hr
C
30 km / hr
D
36 km / hr
Correct Answer: Option A

Let the whole distance travelled be x km and the average speed of the car for the whole journey by y km / hr.

Then, ( x/3)/10 + ( x+ 3)/20 + (x + 3)/60 = x/y

=> x/30 + x/60 + x/180 = x/y

=> 1y/18 = 1 <=> y = 18 km / hr

Question 16
Robert is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M. ?

A
8 kmph
B
11 kmph
C
12 kmph
D
14 kmph
Correct Answer: Option C

Let the distance travelled be x km.
Then, x/10 - x/15 = 2
<=> 3x - 2x = 60
<=> x = 60 km

Time taken to travel 60 km at 10 km/hr :
= 60/10 hrs
= 6 hrs.

So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.

∴ Required speed = 60 /5 kmph = 12 kmph.

Question 17
With a uniform speed a car covers the distance in 8 hours. Had the speed been increased by 4 km/hr, the same distance could have been covered in 7 hours 30 minutes. What is the distance covered ?

A
420 km
B
480 km
C
Cannot be determined
D
None of these
Correct Answer: Option B

Let the distance be X km.

Then , X/7 - X/8 =4

<=> 2X/15 - X/8 = 4

<=> X = 480 km

Question 18
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is :

A
50 km
B
56 km
C
70 km
D
80 km
Correct Answer: Option A

Let the actual distance travelled be x km.

Then, x /10 = ( x + 20)/(14)

<=> 14x = 10x + 200

<=> 4x = 200

<=> x = 50 km

Question 19
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is :

A
1 hour
B
2 hours
C
3 hours
D
4 hours
Correct Answer: Option A

Let the duration of the flight be x hours.

Then, 600 - 600 = 200
x x + (1/2)

600 - 1200 = 200
x 2x + 1

x(2x + 1) = 3

2x2 + x - 3 = 0

(2x + 3)(x - 1) = 0

x = 1 hr.      [neglecting the -ve value of x]

Question 20
It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the car is :
A
2 : 3
B
3 : 2
C
3 : 4
D
4 : 3
Correct Answer: Option C

Let the speed of the train be x km/hr and that of the car be y km/hr.

Then, 120 + 480 = 8       1 + 4 = 1 ....(i)
x y x y 15

And, 200 + 400 = 25     1 + 2 = 1 ....(ii)
x y 3 x y 24

Solving (i) and (ii), we get: x = 60 and y = 80.

Ratio of speeds = 60 : 80 = 3 : 4.

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