Quantitative Aptitude

General Questions

Quantitative Aptitude Exercise Mode

General Questions

Practice and master this topic with our carefully crafted questions.

10 Questions
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Question 1
In how many minutes will Samir cover a distance of 800 m, if he runs at speed of 10 km/hr?

A
5 min
B
4 min 48 sec
C
4 min 40 sec
D
5 min 12 sec
Correct Answer: Option B

samir's speed = 10 Km/hr
                     = (10 x 5/18) m/sec
                     = 50/18 m/sec

Time taken to cover 800 m = (800 / (50/18) ) sec
                                       = (800 x 18/50) sec
                                       = 288 sec
                                       = 4 min 48 sec

Question 2
How long will a boy take to run round a square field of side 35 metres, if he runs at the rate of 9 km/hr ?

A
50 sec
B
52 sec
C
54 sec
D
56 sec
Correct Answer: Option D

Speed = 9 km/hr = (9 x 5/18) m/sec
          = 5/2 m/sec

Distance = (35 x 4) m = 140 m

Time taken = (140 x 2/5 ) sec = 56 sec

Question 3
A car is running at a speed of 108 kmph. What distance will it cover in 15 seconds ?

A
45 metres
B
55 metres
C
450 metres
D
Cannot be determined
E
None of these
Correct Answer: Option C

Speed = 108 kmph
          = (108 x 5/18) m/sec
          = 30 m/sec

∴ Distance covered in 15 sec = (30 x 15) m
                                          = 450 metres.

Question 4
A truck covers a distance of 550 metres in 1 minute where as a bus covers a distance of 33 kms in 45 minutes. The ratio of their speed is :

A
3 : 4
B
4 : 3
C
3 : 5
D
50 : 3
Correct Answer: Option A

Ratio of speeds :
   = (550/60 x 18/5 ) : (33/45 x 60)
   = 33 : 44 = 3 : 4

Question 5
The ratio between the speed of two trains is 7 : 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is :

A
70 km / hr
B
75 km / hr
C
84 km / hr
D
87.5 km / hr
Correct Answer: Option D

Let the speeds of two trains be 7x and 8x km / hr.
Then, 8x = 400/4 = 100
=> x = (100/8) = 12.5

Speed of first train = (7 x 12.5 ) km / hr
                           = 87.5 km / hr

Question 6
Sound is said to travel in air at about 1100 feet per second. A man hears the axe striking the tree, 11/5 seconds after he sees it strike the tree. How far is the man from the wood chopper?

A
2197 ft
B
2420 ft
C
2500 ft
D
2629 ft
Correct Answer: Option B

Distance = (1100 x 11/5) feet = 2420 feet.

Question 7
The speed of a car increases by 2 kms after every one hour. If the distance travelled in the first one hour was 35 kms, what was the total distance travelled in 12 hours ?

A
456 kms
B
482 kms
C
552 kms
D
556 kms
E
None of these
Correct Answer: Option C

Total distance travelled in 12 hours = (35 + 37 + 39 + ---- upto 12 terms).

This is an A.P :
First term, a = 35,
Number of terms, n = 12,
Common difference, d = 2.

∴ Required distance = 12/2 [2 x 35 + (12-1) x 2]
                             = 6 (70 + 22 )
                             = 552 km

Question 8
A person has to cover a distance of 6 km in 45 minutes. If he cover one-half of the distance in two-thirds of the total time; to cover the remaining distance in the remaining time, his speed (in km/hr) must be :

A
6
B
8
C
12
D
15
Correct Answer: Option C

Remaining distance = 3 km
Remaining time = (1/3 x 45) min
                       = 15 min
                       = 1/4 hour.

∴ Required speed = (3 x 4) km / hr = 12 km / hr

Question 9
A salesman travels a distance of 50 km in 2 hours and 30 minutes. How much faster, in kilometres per hour, on an average, must he travel to make such a trip in 5/6 hour less time ?

A
10
B
20
C
30
D
None of these
Correct Answer: Option A

Time required = (2 hrs 30 min - 50 min) = 1 hr 40 min
                     = 1x(2/3) hrs

∴ Required speed = 50 x 3/5 km / hr = 30 km / hr.

∴ Original speed = 50 x 2/5 km / hr = 20 km / hr.

∴ Difference in speed = 30 - 20 km / hr = 10 km / hr.

Question 10
A man travelled from the village to the post-office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village.

A
40 km
B
20 km
C
60 km
D
None of these
Correct Answer: Option B

Average speed = (2xy / x + y) km/hr
        = (2 x 25 x 4 / 25 + 4) km/hr
        = 200 / 29 km/hr

Distance travelled in 5 hours 48 minutes
i.e, 5 x (4 / 5) hrs = (200 /29 x 29 / 5) km = 40 km

∴ Distance of the post office from the village = (40 / 2) = 20 km

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