Arithmetic Reasoning - Expert Level
Practice and master this topic with our carefully crafted questions.
Let the daughter's age be x years.
Then, father's age = (3x) years.
Mother's age = (3x - 9) years; Son's age = (x + 7) years.
So, x + 7 = (3x-9)/2 2x + 14 = 3x - 9 x = 23.
Therefore Mother's age = (3X - 9) = (69 - 9) years = 60 years.
Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 48 3x = 48 x = 16.
Let the number of cows be x and the number of hens be y.
Then, 4x + 2y = 2 (x + y) + 14 <=> 4x + 2y = 2x + 2y + 14 <=> 2x = 14 <=> x = 7.
There are total 5 ways.
we have only one kg of weight so,
2kg = 1kg + 1kg
4kg = 1 + 2 + 1
8kg = 1 + 2 + 4 + 1
16kg = 1 + 2 + 4 + 8 + 1
31kg = 1 + 2 + 4 + 8 + 16
So 5 weights are needed.
Given that 50 paise and 25 paise coins are in the ratio of 7:3, they can be either 7 & 3 or 14 & 6.
As total 20 coins also includes Rs. 1 coins, so 50 paise & 25 paise coins are 7 & 3 respectively & Rs. 1 coins are 10.
Total amount = (100x10) + (50x7) + (25x3) = 1425 paise or Rs.14.25.
3T+12C = 48,250----(1)
21T+36C = ?
multiply eq (1) with 3
i.e, = 3( 7T + 12C ) = 48,250*3
21T+36C = ₹ 1,44,750/-
If there are x girls, then
x + 15x = 1200
16x = 1200
x= 1200/16 = 75
Let 'n' number of days it take to complete.
we know that sum of n number= n/2[2a+(n-1)d]
where a=20,d=1;
n/2[ 2 x 20 + (n-1)1 ]=275
n[n+39]=550
+ 39n - 550 = 0
+ 50n - 11n - 550 = 0
(n-11) (n-50) = 0
n-11 = 0;
n = 11(Days).
As clear from the figure itself, triangle OQX and triangle O'PX are similar.
So,
OQ/O'P = OX/O'X
=> OX = (7/9) x (O'X)
And since, OX + O'X = 20
=> (7/9) x (O'X ) + O'X = 20
=> O'X = 45/4
Suman is brilliant and dishonest is P ~ R
Suman is brilliant and dishonest iff suman is rich is
Q (P
~ R)
Negative of statement is expressed as
~ (Q (P
~ R)).