Arithmetic Reasoning Arithmetic Reasoning - Expert Level

Let the daughter's age be x years.

Then, father's age = (3x) years.

Mother's age = (3x - 9) years; Son's age = (x + 7) years.

So, x + 7 = (3x-9)/2 2x + 14 = 3x - 9 x = 23.

Therefore Mother's age = (3X - 9) = (69 - 9) years = 60 years.

Suppose the boy got x sums right and 2x sums wrong.

Then, x + 2x = 48 3x = 48 x = 16.

Let the number of cows be x and the number of hens be y.

Then, 4x + 2y = 2 (x + y) + 14 <=> 4x + 2y = 2x + 2y + 14 <=> 2x = 14 <=> x = 7.

There are total 5 ways.

we have only one kg of weight so,

2kg = 1kg + 1kg

4kg = 1 + 2 + 1

8kg = 1 + 2 + 4 + 1

16kg = 1 + 2 + 4 + 8 + 1

31kg = 1 + 2 + 4 + 8 + 16

So 5 weights are needed.

Given that 50 paise and 25 paise coins are in the ratio of 7:3, they can be either 7 & 3 or 14 & 6.

As total 20 coins also includes Rs. 1 coins, so 50 paise & 25 paise coins are 7 & 3 respectively & Rs. 1 coins are 10.

Total amount = (100x10) + (50x7) + (25x3) = 1425 paise or Rs.14.25.

3T+12C = 48,250----(1)

21T+36C = ?

multiply eq (1) with 3

i.e, = 3( 7T + 12C ) = 48,250*3

21T+36C = ₹ 1,44,750/-

If there are x girls, then

x + 15x = 1200

16x = 1200

x= 1200/16 = 75

Let 'n' number of days it take to complete.

we know that sum of n number= n/2[2a+(n-1)d]

where a=20,d=1;

n/2[ 2 x 20 + (n-1)1 ]=275

n[n+39]=550

+ 39n - 550 = 0

+ 50n - 11n - 550 = 0

(n-11) (n-50) = 0

n-11 = 0;

n = 11(Days).

As clear from the figure itself, triangle OQX and triangle O'PX are similar.

So,

OQ/O'P = OX/O'X

=> OX = (7/9) x (O'X)

And since, OX + O'X = 20

=> (7/9) x (O'X ) + O'X = 20

=> O'X = 45/4

Suman is brilliant and dishonest is P ~ R

Suman is brilliant and dishonest iff suman is rich is

Q  (P ~ R)

Negative of statement is expressed as

~ (Q  (P  ~ R)).