1.  A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?
A. 12
B. 16
C. 18
D. 24

Answer: Option B

Explanation:

Suppose the boy got x sums right and 2x sums wrong.

Then, x + 2x = 48 3x = 48 x = 16.