General Questions
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| = ₹ 15000. |
of the amount in 10 years ?Let sum = X. Then,
S.I. = 2X / 5 , Time = 10 years.
| Rate = | ![]() |
100 x 2X | % |
= 4% |
| X x 5 x 10 |
Let the sum lent to C be ₹ X. Then,
<=> 7X /25 = (1120 - 700) <=> ₹ (420 x 25) / 7 = ₹ 1500 |
<=> 4500 <=> R1 - R2 = 1350 / 4500 = 0.3% |
Let the sum invested in Scheme A be ₹ X and
that in Scheme B be ₹ (13900 - X).
= 3508 <=> 28x - 22x = 350800 - (13900 x 22) <=> 6x = 45000 <=> x = 7500. So, sum invested in Scheme B = ₹ (13900 - 7500) = ₹ 6400. |
Let the first part be ₹ A.
second part be ₹ B
and third part be Rs C
According to the question.
(A x 2 x 3)/100 = (B x 3 x 4)/100 = (C x 4 x 5)/ 100
⇒ 3A = 6B = 10C = k
∴ A = k/3, B = k/100 and C = k /10
Now, A + B + C = 1440
⇒ k/3 + k/6 + k/10 = 1440 ⇒ k = 2400
∴ so the difference = k/3 - k/10 = 7k/30 = 7/30 x 2400 = ₹ 560
Money paid in cash = ₹ 1000.
Balance payment = ₹ (20000 - 1000)
= ₹ 19000.
Let the second amount be ₹ X. Then,
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Let the sum be ₹ X. Then,
<=> 25X - 20X = 250000 |
Let the sum lent at 10% be ₹ X and that lent at 9% be ₹ (2600 - X). Then,
<=> 50X = (2600 x 54) - 54X
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= 1120
x =