Quantitative Aptitude

General Questions

Quantitative Aptitude Exercise Mode

General Questions

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Question 1
Find the simple interest on ₹ 3000 at 6% per annum for the period from 4th Feb., 2017 to 18th April, 2017.

A
₹ 47.50
B
₹ 37.50
C
₹ 27.50
D
None of these
Correct Answer: Option B

Time = (24 + 31 + 18) days = 73 days

= 73 / 365 year = 1/ 5 year.

P = ₹ 3000 and R = 6% p.a = 25/4 % p.a.

S.I. = ₹ 3000 x 25/4 x 1/5 x 1/100 = ₹ 37.50

Remark : The day on which money is deposited is not counted while the day on which money is withdrawn is counted.

Question 2
A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6 p.a for 2 years. Find his gain in the transaction per year.

A
₹ 112.50
B
₹ 125
C
₹ 150
D
₹ 167.50
Correct Answer: Option A

Gain in 2 years

= ₹  5000 x 25 x 2 - 5000 x 4 x 2
4 100 100

= ₹  (625 - 400)
= ₹  225.

Gain in 1 year = ₹ 225= ₹ 112.50
2

Question 3
A sum of ₹ 12,500 amounts to ₹ 15,500 in 4 years at the rate of simple interest . What is the rate of interest ?

A
3%
B
4%
C
5%
D
6%
E
None of these
Correct Answer: Option D

S.I. = ₹ (15500 - 12500) = ₹ 3000.

Rate = 100 x 3000 % = 6%
12500 x 4

Question 4
Reena took a loan of ₹ 1200 with simple interest for as many years as the rate of interest. If she paid ₹ 432 as interest at the end of the loan period, what was the rate of interest?

A
3.6
B
6
C
18
D
Cannot be determined
E
None of these
Correct Answer: Option B

Let rate = R% and time = R years.

Then, 1200 x R x R = 432
100

12R2 = 432

R2 = 36

R = 6.

Question 5
A sum fetched a total simple interest of ₹ 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?

A
₹ 4462.50
B
₹ 8032.50
C
₹ 8900
D
₹ 8925
E
None of these
Correct Answer: Option D

Principal
= ₹ 100 x 4016.25
9 x 5
= ₹ 401625
45
= ₹ 8925.
Question 6
What is the present worth of ₹ 132 due in 2 years at 5% simple interest per annum ?

A
₹ 112
B
₹ 118.50
C
₹ 120
D
₹ 122
Correct Answer: Option C

Let the present worth be ₹ X. Then, S.I. = ₹ (132-X)

∴ ₹ X x 5 x 2
100

= ₹ 132- X

<=> 10X = 13200 - 100X

<=> 110X = 13200

<=> X = 120

Question 7
A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay ₹ 5400 interest only for the period. The principal amount borrowed by him was:

A
₹ 2000
B
₹ 10,000
C
₹ 15,000
D
₹ 20,000
Correct Answer: Option C

Principal = ₹ 100 x 5400 = ₹15000.
12 x 3

Question 8
₹ 800 becomes Rs. 956 in 3 years at a certain rate of simple interest. If the rate of interest is increased by 4%, what amount will ₹ 800 become in 3 years ?

A
₹ 1020.80
B
₹ 1025
C
₹ 1052
D
Data inadequate
E
None of these
Correct Answer: Option C

S.I. = ₹ (956 - 800) = ₹ 156.

∴ Time = 100 x 156 years = 3 years.
800 x 3

= 6%

New Rate = 6 + 4% = 10%.

New S.I. = ₹ (800 x 21/2 x 3/100)

= ₹ 252.

New amount = ₹ (800 + 252) = ₹ 1052

Question 9
In how many years, ₹ 150 will produce the same interest @ 8% as ₹ 800 produce in 3 years @ 4% ?

A
6
B
8
C
9
D
12
Correct Answer: Option C

P = ₹ 800, R = 4% = 9/2%,

T = 3 years, Then,

S.I. = ₹ (800 x 9/2 x 3/100) = ₹ 108.

Now, P = ₹ 150, S.I. = ₹ 108, R = 8%.

Time = 100 x 108 years = 9 years.
150 x 8

Question 10
A certain amount earns simple interest of ₹ 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?

A
₹ 35
B
₹ 245
C
₹ 350
D
Cannot be determined
E
None of these
Correct Answer: Option D

We need to know the S.I., principal and time to find the rate.

Since the principal is not given, so data is inadequate.

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