General Questions
Practice and master this topic with our carefully crafted questions.
Let the cost of the brand be ₹ X per kg.
C.P. of 5 kg = (2 x 200 + 3 x X) = ₹ (400 + 3X)
S.P of 5 kg = ₹ (5 x 177) = ₹ 885
[885 - (400 + 3X)]/(400 + 3X) x 100 = 18
24250 – 150X = 3600 + 27X
177X = 20650 => X = 116 
So, cost of the other brand = ₹ 116.66.
Let the cost price of table = ₹ N
Then, selling price with 15% gain
= (100 + Gain%) x CP/100
= (100 + 15)% x CP/100
= (115 x N)/100 = ₹ 115N/100
Now CP = [(100 - 25%) x CP] / 100 = ₹75N/100
New SP = ₹ (115N/100) - 60
Now, according to the question,
[[(115/100 ) - 60) - (75N/100)] / (75N/100)] x 100 = 32
[[(115N - 6000 - 75N)/100 ] / (75N/100)] x 100 = 32
[(40N - 6000)/75N] x 100 =32
(40N - 6000)/(3N x 4) = 32
160N - 24000 = 96N
160N - 96N = 24000
64N = 24000
N = 24000/64
N = ₹375
The cost price of table is ₹ 375.
Price at which the TV set is bought = ₹ 12,500
Discount offered = 20%
Marked Price = 12500 x 100/80 = ₹ 15625
The total amount spent on transport and installation = 125 + 250 = ₹ 375\Total price of TV set = 15625 + 375 = ₹ 16000
The price at which the TV should be sold to get a profit of 10% if no discount was offered = 16000 x 110/100 = ₹ 17600
Cost price (CP) = 500
Selling Price (SP) = 576
Mark-up price (MP) = 900
Again SP = MP [( 1 - r/100)2] [r - rate of discount in %]
576 = 900 (1 - r/100)2
24/30 = (1 - r/100)
r = 20%
Again, new SP = MP (1 + r/100)2
= 900 (1 + 20/100)2
= 1296
New, profit percentage = [(SP - CP)/CP] X 100
= [( 1296 - 500 ) / 500 ] x 100 = 159.2%
Amount paid in 1st service = 100 (suppose)
Amount paid in 2nd service = 90
Amount paid in 3rd service = 81
Amount paid in 4th service = 72.9
Amount paid in 5th service = 60
Total amount paid = 403.9
Discount = 500 - 403.9 = 96.1
Discount % = 96.1 / 500 X 100 = 19.42%
Ratio of selling price and Cost Price,
SP : CP = 12 : 9 = 4 : 3
Profit of 3 oranges = Re 1 (Let CP = Re 1)
Profit = 1/3 = 33.33%
And, Discount = 11.11%
Since, CP : SP : MP = 3 : 4 : 4.5
Profit doubles that of discount.
So, % point discount = 33.33% -11.11% = 22.22% point.
You must know that the company is able to deliver only 90% of manufactured pens. So let k be the manufacturing price of a pen
Then,
Total income (including 25% profit) = 8000 x k x 1.25
Also this same income is obtained by selling 90% manufactured at ₹10 which is equal to 7200 x 10.
8000 x K x 1.2 = 7200 x 10
K = ₹ 7.2 ( 90% of 8000 = 7200)
Consider actual price of 1 g goods = Re. 1.
He sells the product equals to ₹ 90 only (10% less weighing)
Again MP = ₹ 1.8 and SP = 1.35 for 1 g.
Thus he gives the goods worth ₹ 90 and charges ₹ 135 after 25% discount.
Thus the profit % = [(135 - 90) / 90 ] x 100
= 50%
By Hit and Trial ,
Case I t = ₹ 400 and q = 20 unit
Then, from option (a),
Total profit = 600q - 5t
= 600 x 20 - 5 x 400
= 12000 - 2000 = ₹ 10000
Case II t ₹ 600 and q = 25 units
Total profit = 600q - 5t
⇒ 600 x 25 - 5 x 600
⇒ 600(25 - 5)
⇒ 600 x 20
∴ ₹ 12000
Let the cost price of first bicycle be ₹ P.
Then, the cost price of second bicycle = ₹ (1600 - P)
According to the given condition,
⇒ [20% of P + 10% of (1600 - P )] - [10% of P + 20% of (1600 - P)] = 5
⇒ [(20P/100) + [10 x (1600 - P)]/100] - [(10P/100) + {20 x (1600 - P)}/100] = 5
⇒ (P/5 + (1600 - P)/10) - (P/10 + (1600 - P)/5) = 5
⇒ P/5 - P/10 + (1600 - P)/10 - (1600 - P)/5 = 5
⇒ 2P = 1600 + 50
⇒ P = 1650/2 = 825
∴ Cost of second bicycle = (1600 - 825) = ₹ 775
∴ Required difference = 825 - 775 = ₹ 50