Profit & Loss General Questions

Let the cost of the brand be ₹ X per kg.

 C.P. of 5 kg = (2 x 200 + 3 x X) = ₹ (400 + 3X)

 S.P of 5 kg = ₹ (5 x 177) = ₹ 885

 [885 - (400 + 3X)]/(400 + 3X) x 100 = 18

 24250 – 150X = 3600 + 27X

 177X = 20650 => X = 116 

So, cost of the other brand = ₹ 116.66.

Let the cost price of table = ₹ N

Then, selling price with 15% gain

= (100 + Gain%) x CP/100

= (100 + 15)% x CP/100

= (115 x N)/100 = ₹ 115N/100

Now CP = [(100 - 25%) x CP] / 100 = ₹75N/100

New SP = ₹ (115N/100) - 60

Now, according to the question,

[[(115/100 ) - 60) - (75N/100)] / (75N/100)] x 100 = 32

 [[(115N - 6000 - 75N)/100 ] / (75N/100)] x 100 = 32

 [(40N - 6000)/75N] x 100 =32

 (40N - 6000)/(3N x 4) = 32

 160N - 24000 = 96N

 160N - 96N = 24000

 64N = 24000

 N = 24000/64

 N = ₹375

 The cost price of table is ₹ 375.

Price at which the TV set is bought = ₹ 12,500

Discount offered = 20%

Marked Price = 12500 x 100/80 = ₹ 15625

The total amount spent on transport and installation = 125 + 250 = ₹ 375\Total price of TV set = 15625 + 375 = ₹ 16000

The price at which the TV should be sold to get a profit of 10% if no discount was offered = 16000 x 110/100 = ₹ 17600

Cost price (CP) = 500
Selling Price (SP) = 576
Mark-up price (MP) = 900

Again SP = MP [( 1 - r/100)²] [r - rate of discount in %]

576 = 900 (1 - r/100)²
24/30 = (1 - r/100)
r = 20%

Again, new SP = MP (1 + r/100)²

= 900 (1 + 20/100)²

= 1296

New, profit percentage = [(SP - CP)/CP] X 100

= [( 1296 - 500 ) / 500 ] x 100 = 159.2%

Amount paid in 1st service = 100 (suppose)

Amount paid in 2nd service = 90

Amount paid in 3rd service = 81

Amount paid in 4th service = 72.9

Amount paid in 5th service = 60

 Total amount paid = 403.9

Discount = 500 - 403.9 = 96.1

 Discount % = 96.1 / 500 X 100 = 19.42%

Ratio of selling price and Cost Price,

SP : CP = 12 : 9 = 4 : 3

Profit of 3 oranges = Re 1 (Let CP = Re 1)

Profit = 1/3 = 33.33%

And, Discount = 11.11%

Since, CP : SP : MP = 3 : 4 : 4.5

Profit doubles that of discount.

So, % point discount = 33.33% -11.11% = 22.22% point.

You must know that the company is able to deliver only 90% of manufactured pens. So let k be the manufacturing price of a pen

Then,

Total income (including 25% profit) = 8000 x k x 1.25

Also this same income is obtained by selling 90% manufactured at ₹10 which is equal to 7200 x 10.

 8000 x K x 1.2 = 7200 x 10

 K = ₹ 7.2      ( 90% of 8000 = 7200)

Consider actual price of 1 g goods = Re. 1.

He sells the product equals to ₹ 90 only (10% less weighing)

Again MP = ₹ 1.8 and SP = 1.35 for 1 g.

Thus he gives the goods worth ₹ 90 and charges ₹ 135 after 25% discount.

Thus the profit % = [(135 - 90) / 90 ] x 100

                               = 50%

By Hit and Trial ,

Case I t = ₹ 400 and q = 20 unit

Then, from option (a),

Total profit = 600q - 5t

= 600 x 20 - 5 x 400

= 12000 - 2000 = ₹ 10000

Case II t ₹ 600 and q = 25 units

Total profit = 600q - 5t

⇒ 600 x 25 - 5 x 600

⇒ 600(25 - 5)

⇒ 600 x 20

∴ ₹ 12000

Let the cost price of first bicycle be ₹ P.

Then, the cost price of second bicycle = ₹ (1600 - P)

According to the given condition,

⇒ [20% of P + 10% of (1600 - P )] - [10% of P + 20% of (1600 - P)] = 5

⇒ [(20P/100) + [10 x (1600 - P)]/100] - [(10P/100) + {20 x (1600 - P)}/100] = 5

⇒ (P/5 + (1600 - P)/10) - (P/10 + (1600 - P)/5) = 5

⇒ P/5 - P/10 + (1600 - P)/10 - (1600 - P)/5 = 5

⇒ 2P = 1600 + 50

⇒ P = 1650/2 = 825

∴ Cost of second bicycle = (1600 - 825) = ₹ 775

∴ Required difference = 825 - 775 = ₹ 50