General Questions
Practice and master this topic with our carefully crafted questions.
| Speed= | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
| Speed of the train relative to man = | ![]() |
125 | m/sec |
| 10 |
| = | ![]() |
25 | m/sec. |
| 2 |
| = | ![]() |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
| Speed = | ![]() |
144 x 5 | m/sec = 40 m/sec. |
| 18 |
Time taken = |
![]() |
100 | sec = 2.5 sec. |
| 40 |
| Speed = | ![]() |
72 x 5 | m/sec = 20 m/sec. |
| 18 |
Total distance covered = (110 + 132)m = 242 m.
Required time = |
![]() |
242 | sec = 12.1 sec. |
| 20 |
Formula for converting from km/hr to m/s:
| X km/hr = | ![]() |
X x | 5 | ![]() |
m/s. |
| 18 |
| Therefore, Speed = | ![]() |
45 x | 5 | m/sec |
= | 25 | m/sec. |
| 18 | 2 |
Total distance to be covered = (360 + 140) m
= 500 m.
| Formula for finding Time = | ![]() |
Distance | ![]() |
| Speed |
Required time = |
![]() |
500 x 2 | sec |
= 40 sec. |
| 25 |
miles long. The train is
mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
| Total distance covered |
|
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Time taken |
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| = 3 min. |
Let the length of the train be x metres and its speed by y m/sec.
| Then, | x | = 15 y = |
x | . |
| y | 15 |
![]() |
x + 100 | = | x |
| 25 | 15 |
15(x + 100) = 25x
15x + 1500 = 25x
1500 = 10x
x = 150 m.
| Speed = | ![]() |
78 x | 5 | ![]() |
m/sec | = | ![]() |
65 | ![]() |
m/sec. |
| 18 | 3 |
Time = 1 minute = 60 seconds.
Let the length of the tunnel be x metres.
| Then, | ![]() |
800 + x | ![]() |
= | 65 |
| 60 | 3 |
3(800 + x) = 3900
x = 500.
| Speed = | ![]() |
300 | ![]() |
m/sec = | 50 | m/sec. |
| 18 | 3 |
Let the length of the platform be x metres.
| Then, | ![]() |
x + 300 | ![]() |
= | 50 |
| 39 | 3 |
3(x + 300) = 1950
x = 350 m.
Let the length of the train be x metres and its speed by y m/sec.
| Then, | x | = 8 x = 8y |
| y |
| Now, | x + 264 | = y |
| 20 |
8y + 264 = 20y
y = 22.
Speed = 22 m/sec = |
![]() |
22 x | 18 | ![]() |
km/hr = 79.2 km/hr. |
| 5 |

m/sec