Answer: Option C
Explanation:
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
|
(100 + 100) |
= 3x |
8 |
24x = 200
x = |
25 |
. |
3 |
So, speed of the faster train = |
50 |
m/sec |
3 |
= |
 |
50 |
x |
18 |
km/hr |
3 |
5 |
= 60 km/hr.