Quantitative Aptitude

General Questions

Quantitative Aptitude Exercise Mode

General Questions

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Question 21
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

A
3.6 sec
B
18 sec
C
36 sec
D
72 sec
Correct Answer: Option C

Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.

   = 36 x 5 m/sec
18

   = 10 m/sec.

Distance to be covered = (240 + 120) m = 360 m.

Time taken = 360 sec = 36 sec.
10
Question 22
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is

A
36
B
45
C
48
D
49
Correct Answer: Option C

Relative speed = (60+ 90) km/hr

   = 150 x 5 m/sec
18

   = 125 m/sec.
3

Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.

Required time = 2000 x 3 sec = 48 sec.
125

Question 23
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

A
5 sec
B
6 sec
C
7 sec
D
10 sec
Correct Answer: Option B

Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.

   = 66 x 5 m/sec
18

   = 55 m/sec.
3

Time taken to pass the man

= 110 x 3 sec = 6 sec.
55

Question 24
A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?

A
230 m
B
240 m
C
260 m
D
270 m
Correct Answer: Option D

Speed = 72 x 5 m/sec = 20 m/sec.
18

Time = 26 sec.

Let the length of the train be x metres.

Then, x + 250 = 20
26

x + 250 = 520

x = 270.

Question 25
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:

A
30 km/hr
B
45 km/hr
C
60 km/hr
D
75 km/hr
Correct Answer: Option C

Let the speed of the slower train be x m/sec.

Then, speed of the faster train = 2x m/sec.

Relative speed = (x + 2x) m/sec = 3x m/sec.

(100 + 100) = 3x
8

24x = 200

x = 25 .
3

So, speed of the faster train = 50 m/sec
3

   = 50 x 18 km/hr
3 5

   = 60 km/hr.

Question 26
Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:

A
9
B
9.6
C
10
D
10.8
Correct Answer: Option D

Relative speed = (60 + 40) km/hr

= 100 x 5 m/sec = 250 m/sec.
18 9

Distance covered in crossing each other = (140 + 160) m = 300 m.

Required time

= 300 x 9 sec = 54 sec = 10.8 sec.
250 5

Question 27
A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?

A
2.5 min
B
3 min
C
3.2 min
D
3.5 min
Correct Answer: Option B

Total distance covered
= ( 7 + 1 ( miles
2 4
= 15 miles.
4

Therefore Time taken
= ( 15 ( hrs
4 x 75
= 1 hrs
20
= ( 1 x 60 ( min.
20
= 3 min.

Question 28
A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:

A
50 m
B
150 m
C
200 m
D
Data inadequate
Correct Answer: Option B

Let the length of the train be x metres and its speed by y m/sec.

Then, x = 15     =>     y = x .
y 15

Therefore x + 100 = x
25 15

=> 15(x + 100) = 25x

=> 15x + 1500 = 25x

=> 1500 = 10x

=> x = 150 m.

Question 29
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?

A
25
B
30
C
40
D
45
Correct Answer: Option B

Speed of the train relative to man = (63 - 3) km/hr
= 60 km/hr
= ( 60 x 5 ( m/sec
18
= ( 50 ( m/sec.
3
Therefore Time taken to pass the man
= ( 500 x 3 ( sec
50
= 30 sec.

Question 30
Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:

A
10
B
18
C
36
D
72
Correct Answer: Option C

Let the speed of each train be x m/sec.

Then, relative speed of the two trains = 2x m/sec.

So, 2x = (120 + 120)
12

=> 2x = 20

=> x = 10.

Therefore Speed of each train

= 10 m/sec = ( 10 x 18 ( km/hr = 36 km/hr.
5

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