Quantitative Aptitude

General Questions 1

Quantitative Aptitude Exercise Mode

General Questions 1

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Question 1
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

A
39, 30
B
41, 32
C
42, 33
D
43, 34
Correct Answer: Option C

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.

Question 2
What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit?

A
1
B
14
C
20
D
21
Correct Answer: Option C

Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.

Number of such number =14

Required percentage = 14 x 100 % = 20%.
70

Question 3
If 20% of a = b, then b% of 20 is the same as:

A
4% of a
B
5% of a
C
20% of a
D
None of these
Correct Answer: Option A

20% of a = b      20 a = b.
100

b% of 20

= b x 20 = 20 a x 1 x 20 = 4 a
100 100 100 100

= 4% of a.

Question 4
If A = x% of y and B = y% of x, then which of the following is true?

A
A is smaller than B.
B
A is greater than B
C
Relationship between A and B cannot be determined.
D
If x is smaller than y, then A is greater than B.
E
None of these
Correct Answer: Option E

x% of y = x x y = y x x = y% of x
100 100

A = B.

Question 5
In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:

A
2700
B
2900
C
3000
D
3100
Correct Answer: Option A

Number of valid votes = 80% of 7500 = 6000.

Valid votes polled by other candidate = 45% of 6000

= 45 x 6000 = 2700.
100

Question 6
Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B.

A
2 : 3
B
1 : 1
C
3 : 4
D
4 : 3
Correct Answer: Option D

5% of A + 4% of B = 2  (6% of A + 8% of B)
3

5  A + 4  B = 2 6  A + 8  B
100 100 3 100 100

1  A + 1  B = 1  A + 4  B
20 25 25 75

1 - 1  A =  4 - 1  B
20 25 75 25

1  A = 1  B
100 75

A = 100 = 4 .
B 75 3

Required ratio = 4 : 3

Question 7
In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is of the number of students of 8 years of age which is 48. What is the total number of students in the school?

A
72
B
80
C
120
D
150
E
100
Correct Answer: Option E

Let the number of students be x. Then,

Number of students above 8 years of age

= (100 - 20)% of x = 80% of x.

80% of x = 48 + 2 of 48
3

80 x = 80
100

x = 100.

Question 8
A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had:

A
588 apples
B
600 apples
C
672 apples
D
700 apples
Correct Answer: Option D

Suppose originally he had x apples.

Then, (100 - 40)% of x = 420.

60 x x = 420
100

x = 420 x 100   = 700.
60

Question 9
Fresh fruit contains 68% water and dry fruit contains 20% water. How much dry fruit can be obtained from 100 kg of fresh fruits ?

A
20
B
30
C
40
D
50
Correct Answer: Option

The fruit content in both the fresh fruit and dry fruit is the same.
Given,
Fresh fruit has 68% water.so remaining 32% is fruit content. Weight of fresh fruits is 100 kg.

Dry fruit has 20% water.so remaining 80% is fruit content.
Let weight if dry fruit be y kg.
Fruit % in fresh fruit = fruit% in dry fruit
∴ (32/100) x 100 = (80/100 ) x y

∴ We get, y = 40 kg

Question 10
The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is ₹ 8748, its purchase price was:

A
10000
B
12000
C
14000
D
16000
Correct Answer: Option B

Purchase Price = ₹ [8748 / (1- 10/100)3]

= ₹ 1200

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