General Questions
Practice and master this topic with our carefully crafted questions.
| Speed in still water = | 1 | (11 + 5) kmph = 8 kmph. |
| 2 |
Let the man's rate upstream be x kmph and that downstream be y kmph.
Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.
|
![]() |
x x 8 | 4 | ![]() |
= (y x 4) |
| 5 |
|
44 | x =4y |
| 5 |
y = |
11 | x. |
| 5 |
Required ratio = |
![]() |
y + x | ![]() |
: | ![]() |
y - x | ![]() |
| 2 | 2 |
| = | ![]() |
16x | x | 1 | ![]() |
: | ![]() |
6x | x | 1 | ![]() |
| 5 | 2 | 5 | 2 |
| = | 8 | : | 3 |
| 5 | 5 |
= 8 : 3.
A man can row three-quarters of a kilometre against the stream in 11
minutes and down the stream in 7
minutes. The speed (in km/hr) of the man in still water is:
We can write three-quarters of a kilometre as 750 metres,
and 11
minutes as 675 seconds.
| Rate upstream = | ![]() |
750 | m/sec |
= | 10 | m/sec. |
| 675 | 9 |
| Rate downstream = | ![]() |
750 | m/sec |
= | 5 | m/sec. |
| 450 | 3 |
Rate in still water = |
1 | ![]() |
10 | + | 5 | m/sec |
| 2 | 9 | 3 |
| = | 25 | m/sec |
| 18 |
| = | ![]() |
25 | x | 18 | km/hr |
| 18 | 5 |
= 5 km/hr.
Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr.
Man's rate against the current = (12.5 - 2.5) km/hr = 10 km/hr.
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15 - x) km/hr.
|
30 | + | 30 | = 4 | 1 |
| (15 + x) | (15 - x) | 2 |
|
900 | = | 9 |
| 225 - x2 | 2 |
9x2 = 225
x2 = 25
x = 5 km/hr.
Speed downstream = (15 + 3) kmph = 18 kmph.
| Distance travelled = | ![]() |
18 x | 12 | km = 3.6 km. |
| 60 |
Let man's rate upstream be x kmph.
Then, his rate downstream = 2x kmph.
(Speed in still water) : (Speed of stream)
| = | ![]() |
2x + x | ![]() |
: | ![]() |
2x - x | ![]() |
| 2 | 2 |
| = | 3x | : | x |
| 2 | 2 |
= 3 : 1.
Suppose he move 4 km downstream in x hours. Then,
| Speed downstream = | ![]() |
4 | ![]() |
km/hr. |
| x |
| Speed upstream = | ![]() |
3 | ![]() |
km/hr. |
| x |
![]() |
48 | + | 48 | = 14 or x = | 1 | . |
| (4/x) | (3/x) | 2 |
So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.
| Rate of the stream = | 1 | (8 - 6) km/hr = 1 km/hr. |
| 2 |
Speed upstream = 7.5 kmph.
Speed downstream = 10.5 kmph.
Total time taken = |
![]() |
105 | + | 105 | hours |
| 7.5 | 10.5 |
= 24 hours.
kmph in still water. If in a river running at 1.5 km an hour, it taken him 50 minutes to row to a place and back, how far off is the place ?Speed downstream = (7.5 + 1.5) kmph = 9 kmph;
Speed upstream = (7.5 - 1.5) kmph = 6 kmph.
Let the required distance be X km. Then,
X/9 + X/6 = 50/60
5/6 x 18