General Questions
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Clearly, the cyclist moves both ways at a speed of 12 km/hr.
So, average speed of the cyclist = 12 km/hr.
The boat sailor moves downstream @ (10 + 4)
i.e 14 km/hr and upstream @ (10 - 4) i.e, 6 km/hr.
So, average speed of the boat sailor :
=
2 x 14 x 6/14 +6
km/hr.
= 42/5 km/hr = 8.4 km/hr.
Since the average speed of the cyclist is greater, he will return to A first.
Let the speed of the stream x mph. Then,
Speed downstream = (10 + x) mph,
Speed upstream = (10 - x) mph.
|
36 | - | 36 | = | 90 |
| (10 - x) | (10 + x) | 60 |
72x x 60 = 90 (100 - x2)
x2 + 48x - 100 = 0
(x+ 50)(x - 2) = 0
x = 2 mph.
hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?Let the speed of the boat in still water be x kmph. Then,
Speed downstream = (x + 3) kmph,
Speed upstream = (x - 3) kmph.
(x + 3) x 1 = (x - 3) x |
3 |
| 2 |
2x + 6 = 3x - 9
x = 15 kmph.
Speed downstream = (5 + 1) kmph = 6 kmph.
Speed upstream = (5 - 1) kmph = 4 kmph.
Let the required distance be x km.
| Then, | x | + | x | = 1 |
| 6 | 4 |
2x + 3x = 12
5x = 12
x = 2.4 km.
Speed downstream = (13 + 4) km/hr = 17 km/hr.
| Time taken to travel 68 km downstream = | ![]() |
68 | hrs |
| 17 |
= 4 hrs.