Data Interpretation

Table Chart 2

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Table Chart 2

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A school has four sections A, B, C, D of Class IX students.

The results of half yearly and annual examinations are shown in the table given below.

ResultNo. of Students
Section ASection BSection CSection D
Students failed in both Exams28231727
Students failed in half-yearly
but passed in Annual Exams		1412813
Students passed in half-yearly
but failed in Annual Exams		617915
Students passed in both Exams64554676

Question 1
Which section has the maximum pass percentage in at least one of the two examinations?

A
A
B
B
C
C
D
D
E
Cannot be determined
Correct Answer: Option D

Pass percentages in at least one of the two examinations for different sections are:

For Section A

[ (14 + 6 + 64) x 100 ] % = [ 84 x 100 ] % 
(28 + 14 + 6 + 64) 112

= 75%.

For Section B

[ (12 + 17 + 55) x 100 ] % = [ 84 x 100 ] % 
(23 + 12 + 17 + 55) 107

= 78.5%.

For Section C

[ (8 + 9 + 46) x 100 ] % = [ 63 x 100 ] % 
(17 + 8 + 9 + 46) 80

= 78.75%.

For Section D

[ (13 + 15 + 76) x 100 ] % = [ 104 x 100 ] % 
(27 + 13 + 15 + 76) 131

= 79.39%

Clearly, the pass percentage is maximum for Section D.

Question 2
If the number of students passing an examination be considered a criteria for comparison of difficulty level of two examinations, which of the following statements is true in this context?

A
Half yearly examinations were more difficult.
B
Annual examinations were more difficult.
C
Both the examinations had almost the same difficulty level.
D
The two examinations cannot be compared for difficulty level.
E
For students of Sections A and B, the annual examinations seem to be more difficult as compared to the half-yearly examinations.
Correct Answer: Option C

Number of students who passed half-yearly exams in the school

= (Number of students passed in half-yearly but failed in annual exams)
+ (Number of students passed in both exams)

= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams)
+ (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true.

Question 3
How many students are there in Class IX in the school?

A
336
B
189
C
335
D
286
E
430
Correct Answer: Option E

Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:

= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430.

Question 4
Which section has the minimum failure rate in half yearly examination?

A
A section
B
B section
C
C section
D
D section
E
Cannot be determined
Correct Answer: Option D

Total number of failures in half-yearly exams in a section

= [ (Number of students failed in both exams)

        + (Number of students failed in half-yearly but passed in Annual exams)

   ] in that section

Therefore Failure rate in half-yearly exams in Section A

= [ No of students of Sec A
failed in half-yearly		 x 100 ] %
Total no of students in Sec A

= [ (28 + 14) x 100 ] %
(28 + 14 + 6 + 64)

= [ 42 x 100 ] %
112

= 37.5%.

Similarly, failure rate in half-yearly exams in:

Section B

[ (23 + 12) x 100 ] % = [ 35 x 100 ] % 
(23 + 12 + 17 + 55) 107

= 32.71%.

Section C

[ (17 + 8) x 100 ] % = [ 25 x 100 ] % 
(17 + 8 + 9 + 46) 80

= 31.25%.

Section D

[ (27 + 13) x 100 ] % = [ 40 x 100 ] % 
(27 + 13 + 15 + 76) 131

= 30.53%.

Clearly, the failure rate is minimum for Section D.

Question 5
Which section has the maximum success rate in annual examination?

A
A Section
B
B Section
C
C section
D
D Section
E
Cannot be determined
Correct Answer: Option A

Total number of students passed in annual exams in a section

= [ (No. of students failed in half-yearly but passed in annual exams)

        + (No. of students passed in both exams)

   ] in that section

Therefore Success rate in annual exams in Section A

    = [ No. of students of Sec A
passed in annual exams		 x 100 ] %
Total number of students in Sec A

    = [ (14 + 64) x 100 ] %
(28 + 14 + 6 + 64)

    = [ 78 x 100 ] %
112

    = 69.64%.

Similarly, success rate in annual exams in:

Section B

[ (12 + 55) x 100 ] % = [ 67 x 100 ] % 
(23 + 12 + 17 + 55) 107

= 62.62%.

Section C

[ (8 + 46) x 100 ] % = [ 54 x 100 ] % 
(17 + 8 + 9 + 46) 80

= 67.5%.

Section D

[ (13 + 76) x 100 ] % = [ 89 x 100 ] % 
(27 + 13 + 15 + 76) 131

= 67.94%.

Clearly, the success rate in annual examination is maximum for Section A.