Alphabet Analogy
Practice and master this topic with our carefully crafted questions.
In this type of questions, two groups of alphabets related to each other in same way, are given. The candidate is required to find out this relationship and choose a group of alphabets which is related in the same way to a third group provided in the question.
Each letter of the first group is moved eight steps forward to obtain the corresponding letter of the second group.
The first, second, third and fourth letters of the first group are moved one, two, three and four steps forward respectively to obtain the corresponding letters of the second group.
Each letter of the first group is replaced by two letters_ one that comes after it and one that comes before it, second group.
BUCKET: ACTVBDJLDFSU :: BONUS:ACNPMOTVRT
Hence, C is the correct option.
Each letter of the first group is moved eight steps forward to obtain the corresponding letter of the second group.
The first and third letters of the first group are each one step backward while the second and fourth letters are each moved one step forward to obtain the corresponding letter of the second group.
Each letter of the first group is movement one state backward to obtain the corresponding letter of the second group.
The first and fourth letters of the first group are respectively moved six steps forward and five steps backward, while the second and third letters are each moved four steps backward to obtain the corresponding letters of the secondary.
The first three letters and the last three letters of the first group are separately reversed in order to obtain the second group.
Each letter of the first group is moved three steps backward to obtain the corresponding letter of the second group.
The letters at odd-numbered position in the first group are each moved third steps forward while those at even=numbered positions are each moved too stay forward to obtain the corresponding letters of the second group.