Data Sufficiency Data Sufficiency - Base Level 1

From I, we have : S = T - 20.

From II, we have : V = T + 30.

Thus, from both I and II, we have : V + S = ( T + 30 ) + ( T - 20 ) = ( 2 T + 10 ).

So, to get the required amount, we need to know the amount that Tarun has.

According to I, Hitesh visited the zoo on any of the week days except Tuesday and Thursday.

According to II, Hitesh's mother reached his house day after Monday i. e. on Tuesday .

Thus, Hitesh visited visied zoo two days before Tuesday i. e. on sunday.

From I, we have :

Number of employees who opted for VRS :

= 18 % of 950 + 6 % of 1100

= 171 + 66 = 237.

From II, we cannot get the required answer until and unless the number of employees in age- group 51 to56 and other age-group is known.

From I, we know that L is T's brother and J's husband . since L is the only son of his parents, T is L's sister.

From II, we know that K is L's daughter.

Thus, from I and II, we conclude that T is the sister of K's father i. e. T is K's aunt.

Clearly to find the code for 'ta' we need to have either only 'ta' or both 'pa' and 'ja' common in I and II. However, none of these conditions is fulfilled. So, the data given in both I and II is also not sufficient to answer the given questions.

In the given statement and I, the common word is 'They' and the common code word is 'nop'. So, 'nop' is the code for 'They'.

In the given statement and II, the common word is 'like' and the common code word is 'al'. So, 'al' is the code for 'like'.

Thus, in the given statement, 'ed' is the code for 'flowers'.

As given in I and II, we have : G = V = K, V + K +A = 32 and A = V + K.

Putting V + K = A in V + K +A = 32, we have : 2A = 32 or A = 16.

Thus, V + K = 16 and V = K. So, V = K = 8. Thus, G = 8.

From I, we know that the serial were screened on 23rd, 24th, 25th and 26th.

Clearly, D was screened second i. e. on 24th, Wednesday.

From II, we know that one serial was screened between A and B. So, A and B were screened first and third, i. e. on 23rd and 25th. But, A was not screened on 25th.

So, A was screened on 23rd and B on 25th. Thus, C was screened on 26th, Friday.

From I, we have : M > V > Q.

From II. we have : T > Q , T > M, P > T.

Combining the above two, we have : P > T > M > V > Q i. e. Q < V < M < T < P.

Clearly, M is in the middle.

From I, we have : N > M, N > P, D > N. Thus, we have : D > N > M > P or D > N > P > M.

But, from II, M earns more than P i. e. D > N > M > P.Also, since P earns less than K and N earns less than only D, so we have : D > N > K M > P or D > N > M >K > P.

Hence either K or M earns more than only the least earner i. e. P.