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Find the least number which leaves a reminder of 3 when divided by 5, 6, 7 and 8, but leaves no reminder when divided by 9 ? |
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Answer: Option A Explanation: First of all, calculate LCM of 5, 6, 7 and 8 which is 840. Suppose Number is K then 840 * K + 3 is divisible by 9. If K = 1, number = (840 × 1) + 3 = 843 which is not divisible by 9 If K = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9 So 1683 is correct answer. |
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