Question 31
Back to Exercise
Find by how much percentage the average of first 10 odd numbers (starting from 1) is greater than the last term ?
- A 991/16 %
- B 900/19 % Correct
- C 874/13 %
- D 719/17 %
Correct Answer: Option B
First ten odd numbers form an arithmetic progression of the form 1,3,5,7,9......
here a = first term = 1
d = common difference = 2
Average of first n numbers = (2a + (n - 1)d)/2
n th term of the AP = a + (n - 1)d
Substituting a = 1, d = 2 and n = 10 in the above formulas
average of first 10 numbers = 10
10 th term of the AP = 19
Therefore average of first 10 terms is 19 - 10 = 9 greater than the last term. Hence the average is greater than the sum by
9/19 X 100 = 900/19 %
Discussion & Comments 0
Share your method, a shortcut, or ask about a step you didn't follow.
No comments yet. Be the first to share your solution!