Square Roots & Cube Roots · Exercise 4 of 6
65 mixed-level square root and cube root questions in the style of IBPS/SBI ("√? = …"), SSC CGL/CHSL, RRB NTPC and Group D, UPSC CSAT, state exams and campus placements. Use them as a timed speed drill.
What is the cube of 1.1?
1.1² = 1.21
1.21 × 1.1 = 1.331
Answer: 1.331
Given √2401 = 49, find √24.01 + √0.2401.
√24.01 = 4.9
√0.2401 = 0.49
4.9 + 0.49 = 5.39
Answer: 5.39
Find √(4/9) + √(16/25).
√(4/9) = 2/3
√(16/25) = 4/5
2/3 + 4/5 = 10/15 + 12/15 = 22/15
Answer: 22/15
What will come in place of ? : (?)² = 1.21 × 0.04 (? positive)
1.21 × 0.04 = 0.0484
? = √0.0484
= 0.22
Answer: 0.22
If x = 3 + 2√2, find √x + 1/√x.
3 + 2√2 = (√2 + 1)², so √x = √2 + 1
1/√x = 1/(√2 + 1) = √2 − 1
Sum = (√2 + 1) + (√2 − 1) = 2√2
Answer: 2√2
What is the square root of 1/0.0081?
√0.0081 = 0.09
√(1/0.0081) = 1/0.09
= 100/9
Answer: 100/9
Find √9 × √16 × √25.
√9 = 3, √16 = 4, √25 = 5
3 × 4 × 5 = 60
Answer: 60
∛9261 + ∛(−1331) = ?
∛9261 = 21 (unit digit 1 → ends in 1; 2³ ≤ 9 → tens digit 2)
∛(−1331) = −11
21 + (−11) = 10
Answer: 10
Find √(1 + 24/25).
1 + 24/25 = 49/25
√(49/25) = 7/5
Answer: 7/5
Simplify (√12 + √27) ÷ √3.
√12 = 2√3 and √27 = 3√3
Sum = 5√3
5√3 ÷ √3 = 5
Answer: 5
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