Using the unit-digit method, find √64009.
Unit digit 9 → root ends in 3 or 7
Drop the last two digits: 640 → 25² = 625 ≤ 640 → tens part 25
Compare with 255² = 65,025: 64,009 is smaller → take 253
Check: 253² = 64,009
Answer: 253
Square Roots & Cube Roots · Exercise 4 of 6
65 mixed-level square root and cube root questions in the style of IBPS/SBI ("√? = …"), SSC CGL/CHSL, RRB NTPC and Group D, UPSC CSAT, state exams and campus placements. Use them as a timed speed drill.
Using the unit-digit method, find √64009.
Unit digit 9 → root ends in 3 or 7
Drop the last two digits: 640 → 25² = 625 ≤ 640 → tens part 25
Compare with 255² = 65,025: 64,009 is smaller → take 253
Check: 253² = 64,009
Answer: 253
Find the value of √(41 − √(21 + √(19 − √9))).
√9 = 3
19 − 3 = 16 → √16 = 4
21 + 4 = 25 → √25 = 5
41 − 5 = 36 → √36 = 6
Answer: 6
√(2.56 × 0.09) = ?
√2.56 = 1.6
√0.09 = 0.3
1.6 × 0.3 = 0.48
Answer: 0.48
What is the square root of 3, correct to two decimal places?
1.73² = 2.9929 and 1.74² = 3.0276
√3 ≈ 1.7320…
Correct to 2 places: 1.73
Answer: 1.73
Find ∛(−27) + ∛64.
∛(−27) = −3
∛64 = 4
−3 + 4 = 1
Answer: 1
A square courtyard has an area of 7,056 m². What is the cost of fencing it at ₹ 5 per metre?
Side = √7,056 = 84 m
Perimeter = 4 × 84 = 336 m
Cost = 336 × 5 = ₹ 1,680
Answer: ₹ 1,680
Find ∛1000 − √100 + √0.01.
∛1000 = 10
√100 = 10
√0.01 = 0.1
10 − 10 + 0.1 = 0.1
Answer: 0.1
What will come in place of ? : √? ÷ 13 = 2.5
√? = 2.5 × 13 = 32.5
? = 32.5²
= 1,056.25
Answer: 1,056.25
1.5² × √0.0225 = ?
1.5² = 2.25
√0.0225 = 0.15
2.25 × 0.15 = 0.3375
Answer: 0.3375
Find √5329 + √4489.
√5329 = 73 (unit digit 9 → 3 or 7; 70² = 4,900 < 5,329 < 75² → 73)
√4489 = 67 (65² = 4,225 < 4,489 → 67)
73 + 67 = 140
Answer: 140
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