General Questions
Practice and master this topic with our carefully crafted questions.
| B runs | 45 | m in 6 sec. |
| 2 |
B covers 300 m in |
![]() |
6 x | 2 | x 300 | sec |
|
| 45 |
A : C = 200 : 182.
| C | = | ![]() |
C | x | A | ![]() |
|||||||
| B | A | B |
| = | ![]() | 182 | x | 200 | ![]() | = 182 : 169. | |||||||
| 200 | 169 |
When C covers 182 m, B covers 169 m.
| When C covers 350 m, |
| B covers | ![]() | 169 | x 350 | m | = 325 m. |
| 182 |
Therefore, C beats B by (350 - 325) m = 25 m.
| When B runs 25 m, A runs | 45 | m. |
| 2 |
| When B runs 1000 m, |
| A runs | ![]() | 45 | x | 1 | x 1000 | m | = 900 m. |
| 2 | 25 |
B beats A by 100 m.
A : B = 100 : 90.
A : C = 100 : 72.
| B : C = | B | x | A | = | 90 | x | 100 | = | 90 | . |
| A | C | 100 | 72 | 72 |
When B runs 90 m, C runs 72 m.
| When B runs 100 m, C runs | ![]() |
72 | x 100 | m |
= 80 m. |
| 90 |
B can give C 20 m.
A : B = 100 : 75
B : C = 100 : 96.
A : C = |
![]() |
A | x | B | ![]() |
= | ![]() |
100 | x | 100 | ![]() |
= | 100 | |
| B | C | 75 | 96 | 72 |
= 100 : 72.
A beats C by (100 - 72) m = 28 m.
times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
| Ratio of the speeds of A and B = | 5 | : 1 = 5 : 3. |
| 3 |
Thus, in race of 5 m, A gains 2 m over B.
2 m are gained by A in a race of 5 m.
| 80 m will be gained by A in race of | ![]() |
5 | x 80 | m |
|
| 2 |
Winning post is 200 m away from the starting point.
A : B = 60 : 45.
A : C = 60 : 40.
|
B | = | ![]() |
B | x | A | ![]() |
= | ![]() |
45 | x | 60 | ![]() |
= | 45 | = | 90 | |
| C | A | C | 60 | 40 | 40 | 80 |
B can give C 10 points in a game of 90.
To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.
While A covers 3 m, B covers 4 m.
| While A covers 360 m, B covers | ![]() |
4 | x 360 | m |
|
| 3 |
= 480 m.
Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
A wins by 20 m.
| A's speed = | ![]() |
5 x | 5 | m/sec |
= | 25 | m/sec. |
| 18 | 18 |
| Time taken by A to cover 100 m = | ![]() |
100 x | 18 | sec |
|
| 25 |
= 72 sec.
Time taken by B to cover 92 m = (72 + 8)
= 80 sec.
B's speed = |
![]() |
92 | x | 18 | kmph |
= 4.14 kmph. |
| 80 | 5 |
| Distance covered by B in 9 sec. |
| = | ![]() | 100 | x 9 | m | = 20 m. |
| 45 |
A beats B by 20 metres.

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