Let the number be x and (28 - x). Then,
x(28 - x) = 192
<=> X2 – 28x + 192 = 0
<=> (x - 16) (x - 12) = 0
<=> x = 16 or x = 12.
So, the numbers are 16 and 12.
A number consists of two digits. If the digits interchange places and the new number is added to the original number , then the resulting number will be divisible by :
Let the four integers be x, x + 2, x + 4 and x + 6.
Then, x + (x + 2) + (x + 4) + (x + 6) = 1284
<=> 4x = 1272
<=> x = 318
Greatest integer = x + 6 = 324
The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 36. What is the difference between the two digits of that number ?