General Questions
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Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P(E) = |
n(E) | = | 7 | . |
| n(S) | 8 |
Total number of balls = (8 + 7 + 6) = 21.
| Let E | = event that the ball drawn is neither red nor green |
| = event that the ball drawn is blue. |
n(E) = 7.
P(E) = |
n(E) | = | 7 | = | 1 | . |
| n(S) | 21 | 3 |
Here, S = {1, 2, 3, 4, ...., 19, 20}.
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
P(E) = |
n(E) | = | 9 | . |
| n(S) | 20 |
Let number of balls = (6 + 8) = 14.
Number of white balls = 8.
| P (drawing a white ball) = | 8 | = | 4 | . |
| 14 | 7 |
Let S be the sample space.
| Then, n(S) | = number of ways of drawing 3 balls out of 15 | |||
| = 15C3 | ||||
|
||||
| = 455. |
Let E = event of getting all the 3 red balls.
n(E) = 5C3 = 5C2 = |
(5 x 4) | = 10. |
| (2 x 1) |
P(E) = |
n(E) | = | 10 | = | 2 | . |
| n(S) | 455 | 91 |
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
P(E) = |
n(E) | = | 2 | = | 1 | . |
| n(S) | 52 | 26 |
Clearly, there are 52 cards, out of which there are 12 face cards.
P (getting a face card) = |
12 | = | 3 | . |
| 52 | 13 |
Let S be the sample space.
| Then, n(S) = 52C2 = | (52 x 51) | = 1326. |
| (2 x 1) |
Let E = event of getting 1 spade and 1 heart.
n(E) |
= number of ways of choosing 1 spade out of 13 and 1 heart out of 13 |
| = (13C1 x 13C1) | |
| = (13 x 13) | |
| = 169. |
P(E) = |
n(E) | = | 169 | = | 13 | . |
| n(S) | 1326 | 102 |
Total number of balls = (2 + 3 + 2) = 7.
Let S be the sample space.
| Then, n(S) | = Number of ways of drawing 2 balls out of 7 | |||
| = 7C2 ` | ||||
|
||||
| = 21. |
Let E = Event of drawing 2 balls, none of which is blue.
n(E) |
= Number of ways of drawing 2 balls out of (2 + 3) balls. | |||
| = 5C2 | ||||
|
||||
| = 10. |
P(E) = |
n(E) | = | 10 | . |
| n(S) | 21 |
In two throws of a dice, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
P(E) = |
n(E) | = | 4 | = | 1 | . |
| n(S) | 36 | 9 |