Question 2
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In how many ways can the letters of NUMBER be arranged so that the vowels occupy only odd positions?
- A 72
- B 720
- C 144 Correct
- D 36
Correct Answer: Option C
Odd positions: 1, 3, 5 → place U and E: 3P2 = 6
Other 4 letters in the remaining 4 places: 4! = 24
6 × 24 = 144
Trap: 72 forgets that U and E can swap.
Answer: 144
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