Question 29
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In how many ways can 12 players be divided into 3 groups of 4 (the groups have no names)?
- A 34,650
- B 5,775 Correct
- C 495
- D 1,925
Correct Answer: Option B
12C4 × 8C4 × 4C4 = 495 × 70 × 1 = 34,650
Groups unnamed: ÷ 3! = 5,775
Trap: 34,650 treats the groups as labelled.
Answer: 5,775
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