LearnFrenzy
Sign in Take a free test

Permutations and Combinations · Discussion forum

Hard Level Question 22 – answer, explanation & discussion

  • 0 comments
  • Answer explained
  • Moderated community
Question 22 Back to Exercise

In how many ways can 3 letters be selected from the letters of ALLAHABAD?

  • A 84
  • B 19 Correct
  • C 10
  • D 35
Correct Answer: Option B

Letters: A × 4, L × 2, H, B, D

All different: 5C3 = 10

Two alike + one other: A or L pair × 4 others = 8

Three alike: AAA = 1

Total = 19

Trap: 84 = 9C3 treats all 9 letters as different.

Answer: 19

Discussion & Comments 0

Share your method, a shortcut, or ask about a step you didn't follow.

No comments yet. Be the first to share your solution!

Post your comment

Comments appear after a quick review by our team.

Search LearnFrenzy

Esc

Quick links