Question 6
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In how many ways can 5 different balls be put into 3 different boxes so that no box is empty?
- A 243
- B 150 Correct
- C 60
- D 125
Correct Answer: Option B
All ways: 3⁵ = 243
Remove one box empty: 3 × 2⁵ = 96, add back two empty: 3
243 − 96 + 3 = 150
Trap: 243 allows empty boxes.
Answer: 150
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