Question 39
Back to Exercise
In how many ways can 3 different numbers be chosen from 1 to 20 so that their sum is even?
- A 570 Correct
- B 1,140
- C 450
- D 120
Correct Answer: Option A
All three even: 10C3 = 120
Two odd, one even: 10C2 × 10 = 450
Total = 570
Answer: 570
Discussion & Comments 0
Share your method, a shortcut, or ask about a step you didn't follow.
No comments yet. Be the first to share your solution!