Question 31
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A box holds 5 different red balls and 3 different white balls. In how many ways can 4 balls be chosen with at least one of each colour?
- A 70
- B 60
- C 65 Correct
- D 55
Correct Answer: Option C
All: 8C4 = 70
All red: 5C4 = 5; all white impossible
70 − 5 = 65
Answer: 65
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