How many solutions does x + y + z = 15 have in integers with each of x, y, z at least 2?
Subtract 2 from each: x′ + y′ + z′ = 9
(9 + 2)C2 = 55
Trap: 136 = 17C2 ignores the minimum.
Answer: 55
Permutations and Combinations · Exercise 4 of 5
65 moderate and difficult permutations and combinations questions, with points on a circle to read, in the style of IBPS / SBI PO and Clerk, RRB NTPC and Group D, UPSC CSAT, state PSC and IT campus placement tests.
How many solutions does x + y + z = 15 have in integers with each of x, y, z at least 2?
Subtract 2 from each: x′ + y′ + z′ = 9
(9 + 2)C2 = 55
Trap: 136 = 17C2 ignores the minimum.
Answer: 55
How many 5-letter arrangements with 2 vowels and 3 consonants can be made from 3 vowels and 5 consonants (no letter repeated)?
Choose: 3C2 × 5C3 = 3 × 10 = 30
Arrange the 5 letters: 5! = 120
30 × 120 = 3,600
Trap: 30 only chooses.
Answer: 3,600
In how many ways can two squares be chosen on a chessboard so that they are not in the same row or column?
First square: 64; second avoids its row and column: 49
Order does not matter: 64 × 49 ÷ 2 = 1,568
Trap: 3,136 counts each pair twice.
Answer: 1,568
In how many ways can 3 identical rooks be placed on a chessboard so that no two share a row or column?
Choose 3 rows and 3 columns: 8C3 × 8C3 = 56 × 56
Match rows to columns: 3! = 6
56 × 56 × 6 = 18,816
Answer: 18,816
In how many arrangements of the letters of BOOK are the two Os not together?
All: 4!/2! = 12
Os together: 3! = 6
Not together = 6
Answer: 6
In how many arrangements of the letters of ASSASSIN are no two Ss next to each other?
Arrange A, A, I, N: 4!/2! = 12
5 gaps; the four Ss take 4 of them: 5C4 = 5
12 × 5 = 60
Trap: 840 is all arrangements.
Answer: 60
How many squares of all sizes are there in a 5 × 5 grid of equal squares?
1² + 2² + 3² + 4² + 5² = 55
Trap: 25 counts only the small squares.
Answer: 55
How many rectangles (including squares) are there in a 5 × 5 grid of equal squares?
6 lines each way: 6C2 × 6C2 = 15 × 15 = 225
Trap: 170 leaves out the squares.
Answer: 225
On a grid, a robot moves from (0, 0) to (6, 4) one unit at a time, only right or up. How many paths are there?
6 rights and 4 ups in any order: 10C4 = 210
Trap: 24 multiplies 6 × 4.
Answer: 210
4 men and 3 women stand in a row so that the women occupy the even-numbered places. In how many ways?
Even places 2, 4, 6 for the women: 3! = 6
Men in places 1, 3, 5, 7: 4! = 24
6 × 24 = 144
Answer: 144
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