General Questions
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4 | x y = (5 x 1 + 4) = 9
--------
5 | y -1 x = (4 x y + 1)
= (4 x 9 + 1) = 37
--------
| 1 -4
Now, 37
when divided successively by 5 and 4,
we get
5 | 37
---------
4 | 7 - 2
---------
| 1 - 3
Respective remainders are 2 and 3.
The square of a natural number never ends in 2.
143642 is not the square of natural number.
Given Exp.
| = [(a + b)2 - 4ab], where a = 476 and b = 424 | |
| = [(476 + 424)2 - 4 x 476 x 424] | |
| = [(900)2 - 807296] | |
| = 810000 - 807296 | |
| = 2704. |
[Ref: By Distributive Law ]
| 8796 x 223 + 8796 x 77 | = 8796 x (223 + 77) |
| = (8796 x 300) | |
| = 2638800 |
On dividing, we get
75) 8485 (113
75
---
98
75
----
235
225
---
10
---
Required number = (8485 - 10)
// Because 10 < (75 - 10)
= 8475.
On dividing we get,
88) 9217 (104
88
----
417
352
----
65
----
Therefore,
Required number = 9217 + (88 - 65)
// Because (88 - 65) < 65.
= 9217 + 23
= 9240.
639 is not divisible by 7
2079 is divisible by each of 3, 7, 9, 11.
Let n = 4q + 3. Then 2n = 8q + 6 = 4(2q + 1 ) + 2.
Thus, when 2n is divided by 4, the remainder is 2.
72 = 9 x8, where 9 and 8 are co-prime.
The minimum value of x for which 73x for which 73x is divisible by 8 is, x = 6.
Sum of digits in 425736 = (4 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 9.
Required value of * is 6.
45 = 5 x 9, where 5 and 9 are co-primes.
Unit digit must be 0 or 5 and sum of digits must be divisible by 9.
Among given numbers, such number is 202860.