General Questions
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| Given Exp. = | 800 | x | 1296 | = 450 |
| 64 | 36 |
72 = 9 x8, where 9 and 8 are co-prime.
The minimum value of x for which 73x for which 73x is divisible by 8 is, x = 6.
Sum of digits in 425736 = (4 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 9.
Required value of * is 6.
Let the given number be 476 xy 0.
Then (4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3.
And, (0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11.
x - y - 3 = 0
y = x - 3
(17 + x + y) = (17 + x + x - 3) = (2x + 14)
x= 2 or x = 8.
x = 8 and y = 5.
Given number = 97215x6
(6 + 5 + 2 + 9) - (x + 1 + 7) = (14 - x), which must be divisible by 11.
x = 3
| (489 + 375)2 - (489 - 375)2 | = ? |
| (489 x 375) |
| (a + b)2 - (a - b)2 | = | 4ab | = 4 |
| ab | ab |
Let 4300731 - x = 2535618
Then x, = 4300731 - 2535618 = 1765113
x = 13p + 11 and x = 17q + 9
13p + 11 = 17q + 9
17q - 13p = 2
q = | 2 + 13p |
| 17 |
| The least value of p for which q = | 2 + 13p | |
| 17 |
is a whole number is p = 26
x = (13 x 26 + 11)
= (338 + 11)
= 349
| 1904 x 1904 | = (1904)2 |
| = (1900 + 4)2 | |
| = (1900)2 + (4)2 + (2 x 1900 x 4) | |
| = 3610000 + 16 + 15200. | |
| = 3625216. |
99 = 11 x 9, where 11 and 9 are co-prime.
By hit and trial, we find that 114345 is divisibleby 11 as well as 9. So, it is divisible by 99.
|
| (a3 - b3) | = (a - b) = (854 - 276) = 578 |
| (a2 + ab + b2) |