Quantitative Aptitude
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Question 11
What is the distance between a tower and an observer if the angle of elevation from the observer’s eye to the top of the tower (height = 50 m) is 30°? The observer is 1.5 m tall.
Correct Answer: Option D
Let AB be the tower and CD be the observer
tan30° = AE/CE
1/3= (AB – CD) / x = (50 – 1.5) / x = 48.5/x
x = 84 m
Question 12
The angle of elevation of the sun is 60°. Find the length of the shadow of a man who is 180 cm tall.
Correct Answer: Option C
Let AB be the man and BC be his shadow
AB = 180
tan60° = AB/BC
3 = 180/BC
BC = 103.92 cm