1.  What is the distance between a tower and an observer if the angle of elevation from the observer’s eye to the top of the tower (height = 50 m) is 30°? The observer is 1.5 m tall.
A. 90 m
B. 30 m
C. 28 m
D. 84 m

Answer: Option D

Explanation:

Let AB be the tower and CD be the observer

tan30° = AE/CE

1/3= (AB – CD) / x = (50 – 1.5) / x = 48.5/x

x = 84 m