C program to reverse an array using pointers Solution, output & explanation

#include <stdio.h>

void reverse(int *a, int n) {
    int *left = a, *right = a + n - 1;
    while (left < right) {
        int t = *left;
        *left++ = *right;
        *right-- = t;
    }
}

int main(void) {
    int a[] = {1, 2, 3, 4, 5, 6};
    int n = sizeof a / sizeof a[0];
    reverse(a, n);
    for (int i = 0; i < n; i++)
        printf("%d ", a[i]);
    printf("\n");
    return 0;
}

6 5 4 3 2 1