What is the output of the following C program? #include int main(void) { int x = 4; if (x & 1 == 0) puts("even"); else puts("odd?!"); return 0; }

Bitwise Operators · Predict the Output · Question 4

Precedence trap: if (x & 1 == 0) – output Answer, explanation & discussion

Question 4 Back to Exercise

What is the output of the following C program?

main.c

#include <stdio.h>

int main(void) {
    int x = 4;
    if (x & 1 == 0)
        puts("even");
    else
        puts("odd?!");
    return 0;
}

Correct Answer: Option B

1 == 0 is evaluated first (0), then x & 0 is 0, so the condition is false even though 4 is even. Compilers warn about it. Write (x & 1) == 0.

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