1.  If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
A. 4 days
B. 5 days
C. 6 days
D. 7 days

Answer: Option A

Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y = 1 and 26x + 48y = 1 .
10 2

Solving these two equations, we get :

x = 1 and y = 1 .
100 200

(15 men + 20 boy)'s 1 day's work

= 15 + 20 = 1 .
100 200 4

15 men and 20 boys can do the work in 4 days.