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A alone can do a certain job in 15 days, while B alone can do it in 10 days. A started the work and was joined by B after 5 days. The work lasted for how many days ? |
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Answer: Option D Explanation: A's 5 days' work = (1/15) x 5 = 1/3 Remaining work = 1 - (1/3) = 2/3 ∴ (A + B)'s 1 day's work = (1/15) + (1/10) = 5/30 = 1/6 ∴ 2/3 work will be finished by (A + B) in (2/3) x 6 days or in 4 days . ∴ Total time taken = (5 + 4) days = 9 days |
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