Question 43
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What is the sum of all the three-digit numbers that can be formed by using each of the digits 1, 2 and 3 exactly once?
- A 1,233
- B 1,332 Correct
- C 1,320
- D 666
Correct Answer: Option B
There are 6 such numbers.
Each digit appears twice in every place.
Sum = 2 × (1 + 2 + 3) × 111 = 2 × 6 × 111 = 1,332
Answer: 1,332
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