Quantitative Aptitude

General Questions

Quantitative Aptitude Exercise Mode

General Questions

Practice and master this topic with our carefully crafted questions.

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Question 21
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

A
504
B
536
C
544
D
548
Correct Answer: Option D

Required number = (L.C.M. of 12, 15, 20, 54) + 8

   = 540 + 8

   = 548.

Question 22
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:

A
75
B
81
C
85
D
89
Correct Answer: Option C

Since the numbers are co-prime, they contain only 1 as the common factor.

Also, the given two products have the middle number in common.

So, middle number = H.C.F. of 551 and 1073 = 29;

First number = 551 = 19.
29

Third number = 1073 = 37.
29

Required sum = (19 + 29 + 37) = 85.

Question 23
The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is:

A
15 cm
B
25 cm
C
35 cm
D
42 cm
Correct Answer: Option C

Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm.

Question 24
Find the highest common factor of 36 and 84.

A
4
B
6
C
12
D
18
Correct Answer: Option C

36 = 22 x 32

84 = 22 x 3 x 7

H.C.F. = 22 x 3 = 12.

Question 25
Which of the following fraction is the largest ?

A
7/8
B
13/16
C
31/40
D
63/80
Correct Answer: Option A

L.C.M. of 8, 16, 40 and 80 = 80.

7 = 70 ;   13 = 65 ;   31 = 62
8 80 16 80 40 80

Since, 70 > 65 > 63 > 62
80 80 80 80

 so 7 > 13 > 63 > 31
8 16 80 40

So, 7 is the largest.
8

Question 26
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:

A
123
B
127
C
235
D
305
Correct Answer: Option B

Required number = H.C.F. of (1657 - 6) and (2037 - 5)

  = H.C.F. of 1651 and 2032 = 127.

Question 27
Which of the following has the most number of divisors?

A
99
B
101
C
176
D
182
Correct Answer: Option C

99 = 1 x 3 x 3 x 11

101 = 1 x 101

176 = 1 x 2 x 2 x 2 x 2 x 11

182 = 1 x 2 x 7 x 13

So, divisors of 99 are 1, 3, 9, 11, 33, .99

Divisors of 101 are 1 and 101

Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176

Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.

Hence, 176 has the most number of divisors.

Question 28
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

A
28
B
32
C
40
D
64
Correct Answer: Option C

Let the numbers be 2x and 3x.

Then, their L.C.M. = 6x.

So, 6x = 48 or x = 8.

The numbers are 16 and 24.

Hence, required sum = (16 + 24) = 40.

Question 29
If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

A
55/601
B
601/55
C
11/120
D
120/11
Correct Answer: Option C

Let the numbers be a and b.

Then, a + b = 55 and ab = 5 x 120 = 600.

The required sum 

1 + 1 = a + b = 55 = 11
a b ab 600 120

Question 30

The H.C.F. of 9 , 12 , 18 and 21 is:
10 25 35 40

A
3/5
B
252/5
C
3/1400
D
63/700
Correct Answer: Option C

Required H.C.F. :

= H.C.F. of 9, 12, 18, 21 = 3
L.C.M. of 10, 25, 35, 40 1400
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