Quantitative Aptitude

General Questions

Quantitative Aptitude Exercise Mode

General Questions

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Question 1
At present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present ?

A
12 years
B
15 years
C
19 and half
D
21 years
Correct Answer: Option B

Let the present ages of Arun and Deepak be 4x years and 3x years respectively.

Then,

4x + 6 = 26 <=> 4x = 20

x = 5.

Deepak's age = 3x = 15 years.

Question 2
A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:

A
14 years
B
18 years
C
20 years
D
22 years
Correct Answer: Option D

Let the son's present age be x years. Then, man's present age = (x + 24) years.

(x + 24) + 2 = 2(x + 2)

 x + 26 = 2x + 4

 x = 22.

Question 3
Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7 : 9, how old is Sachin?

A
16 years
B
18 years
C
28 years
D
24.5 years
E
None of these
Correct Answer: Option D

Let Rahul's age be x years.

Then, Sachin's age = (x - 7) years.

x - 7 = 7
x 9

9x - 63 = 7x

2x = 63

x = 31.5

Hence, Sachin's age =(x - 7) = 24.5 years.

Question 4
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?

A
2 times
B
2.5 times
C
11/4 times
D
3 times
Correct Answer: Option A

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Question 5
Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?

A
24
B
27
C
40
D
Cannot be determined
E
None of these
Correct Answer: Option A

Let the present ages of Sameer and Anand be 5x years and 4x years respectively.

Then, 5x + 3 = 11
4x + 3 9

9(5x + 3) = 11(4x + 3)

45x + 27 = 44x + 33

45x - 44x = 33 - 27

x = 6.

Anand's present age = 4x = 24 years.

Question 6
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:

A
12 years
B
14 years
C
18 years
D
20 years
Correct Answer: Option D

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = 5(x - 6)

54 - x = 5x - 30

6x = 84

x = 14.

Son's age after 6 years = (x+ 6) = 20 years..

Question 7
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?

A
16 years
B
18 years
C
20 years
D
Cannot be determined
E
None of these
Correct Answer: Option A

Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.

Then, (6x + 6) + 4 = 11
(5x + 6) + 4 10

10(6x + 10) = 11(5x + 10)

5x = 10

x = 2.

Sagar's present age = (5x + 6) = 16 years.

Question 8
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

A
18, 20, 28
B
16, 28, 36
C
20, 35, 45
D
None of these
Correct Answer: Option B

Let their present ages be 4x, 7x and 9x years respectively.

Then, (4x - 8) + (7x - 8) + (9x - 8) = 56

20x = 80

x = 4.

Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.

Question 9
A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?

A
32 years
B
36 years
C
40 years
D
48 years
Correct Answer: Option C

Let the mother's present age be x years.

Then, the person's present age = 2 x years.
5

2 x + 8 = 1 (x + 8)
5 2

2(2x + 40) = 5(x + 8)

x = 40.

Question 10
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

A
4 years
B
8 years
C
10 years
D
None of these
Correct Answer: Option A

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

Age of the youngest child = x = 4 years.

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