Question 14
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Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:
- A 6 hours
- B 6(2/3) hours
- C 7 hours Correct
- D 7(1/2) hours
Correct Answer: Option C
| (A + B)'s 1 hour's work = | ![]() |
1 | + | 1 | ![]() |
= | 9 | = | 3 | . |
| 12 | 15 | 60 | 20 |
| (A + C)'s hour's work = | ![]() |
1 | + | 1 | ![]() |
= | 8 | = | 2 | . |
| 12 | 20 | 60 | 15 |
| Part filled in 2 hrs = | ![]() |
3 | + | 2 | ![]() |
= | 17 | . |
| 20 | 15 | 60 |
| Part filled in 6 hrs = | ![]() |
3 x | 17 | ![]() |
= | 17 | . |
| 60 | 20 |
| Remaining part = | ![]() |
1 - | 17 | ![]() |
= | 3 | . |
| 20 | 20 |
| Now, it is the turn of A and B |
| and | 3 | part is filled by A and B in 1 hour. |
| 20 |
Total time taken to fill the tank = (6 + 1) hrs = 7 hrs.


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